Answer:

Step-by-step explanation:
Consider a sketch of the problem as shown in the picture, where:
- Blue line is given by y = 4x + 1.
- Point B is the center of the circle.
- Point A is (-3, 0).
Since the center of the circle lies on the line y = 4x +1 and is tangent to the x-axis at point A, then its radius BA is perpendicular to the x-axis. To find the coordinates of point B, we must replace x = -3 into the blue line equation: y = 4x(-3) + 1 = -11.
So, we know that the center of the circle is at B=(-3, -11). And furthermore, the radius BA is of length r=11.
Since the <em>general equation of the circle</em> of radius lenght r centered at (h, k) is given by

then with h = -3, k = -11 and r= 11, the equation of our circle is

The opposite operation of squaring is to find the square root. I dunno what the original equation is so I can’t help with that
Answer:
Step-by-step explanation:
hello : write this expression
X² + y² + 6x – 2y+3 = 0 in the standard form
(x²+6x) +(y²-2y) +3 = 0
(x²+6x+9 -9) +(y²-2y+1 - 1) +3 = 0
(x²+6x+9) -9 +(y²-2y+1) - 1 +3 = 0
(x+3)²+(y-1)² = 7(the standard form)
but : 7 = (√7)²
<h2>the radius is :
√7</h2>
When x=9 the expression is undefined.
That is because any number over 0 is undefined, including 0/0.