Arc length has a formula that is similar to arc measure, but arc length is expressed in inches or meters or miles, etc., whereas measure is expressed in degrees, like an angle. The formula for each take this into account. Since the arc length is part of the length of the outside of the circle, the formula includes the circumference for a circle.

, where theta is the degree measure of the central angle intersecting the arc you're looking for, and d is the diameter of the circle. Our formula would look like this with the info we have:

which can be simplified to

which can be simplified even further to

. And that's your answer!
First, put it into slope/intercept form so you can see what you've got.
"Slope/intercept form" is <em> y = everything else</em> .
So that means you have to take the equation you have and "solve it for 'y' ".
<u>2y - 10x = 20</u>
Add 10x to each side: 2y = 10x + 20
Divide each side by 2 : <em> y = 5x + 10</em>
There it is.
Now that you have it in that form, you can just look at it and see that the
slope of the line on the graph is 5, and the line crosses the y-axis at 10.
And that's exactly the information you need to graph it. On your graph,
mark a little dot on the y-axis at 10, and draw a line through that dot
with a slope of 5.
Answer:
what do you mean evaluate
Step-by-step explanation: