How many vertice has a hexagonal <br><br>pyramid

PLEASE HELP ME ON THIS!!

Ganezh [65]

Answer:

-6

Step-by-step explanation:

This means what value can I plug into -3x-8 so that I get output 10.

g(x)=-3x-8

g(a)=-3a-8

So we are going to solve g(a)=10 for a.

g(a)=10

-3a-8=10

Add 8 on both sides:

-3a =18

Divide both sides by -3:

a =-6

Check it!

g(-6)=-3(-6)-8=18-8=10 and it's good! :)

3 0

2 years ago

1: Create a single variable linear equation that has no solution. Solve the equation algebraically to prove that it does not hav

OLga [1]

Answer:

(1) y=C, $C\neq0$

(2) x=C

(1) y=0

Step-by-step explanation:

For the linear equation, the power on the solitary variable must be 1.

When the graph of a function crosses/ touches the x-axis than the equation has solution/solutions otherwise it does not has a solution.

When it touches/cresses the x-axis for infinite times then it will have an infinite number of solutions.

(1) The linear equation y-C=0, where y is a variable and C is a non-zero constant, $C \neq 0$ , has the graph parallel to the x-axis. It has no solution as the graph will never cross/touch the x-axis.

Algebraically, in linear equation y-C=0, is independent of x, so there is no value of x for the solution to be exist.

(2) The linear equation x-C=0, where x is a variable and C is a constant, has one solution.

The solution for the equation is

x-C=0

$\Rightarrow x=C$ , where $C\neq0$ .

(3) The linear equation y=0, where y is a variable, has the graph coinciding with the x-axis. So, it has infinitely many solutions.

Algebraically, in linear equation y=0, is independent of x, so for all value of x, the given equation is zero. Hence, there are infinitely many solutions.

3 0

3 years ago

Can someone please help me factorize this one:<br><img src="https://tex.z-dn.net/?f=0.01y%20%7B%7D%5E%7B2%7D%20%20-%20%20%5Cfrac

Scorpion4ik [409]

First let us convert 0.01 into fraction:

$\frac{y^{2}}{100} -\frac{1}{4}$

Now we convert 100 and 4 into perfect squares as follows:

$(\frac{y}{10})^{2}-(\frac{1}{2})^{2}$

Now we use the property of :

$x^{2} -y^{2} =(x+y)(x-y)$

$(\frac{y}{10} +\frac{1}{2} ) (\frac{y}{10} -\frac{1}{2} )$

4 0

3 years ago

Some one help me on this one

aleksandrvk [35]

The answer is III only, or D.

We can start to solve this by knowing what the HL theorem means. The HL theorem, like its name implies, shows says that if a hypotenuse and leg of a triangle are congruent to the hypotenuse and leg of a different triangle, then the triangles are congruent. The only triangle that we see a hypotenuse congruent in is in figure III. In figure II, those congruent sides are both legs while in figure I we just see 2 congruent angles. Now in figure III, we can also see that two legs are congruent because of the reflexive property. That means that the answer is III, or D.

5 0

2 years ago

Whic one is further from zero -3 or -2

Bond [772]

-3 is further away from 0 because if you graph it on a number line, it will show that -3 is one unit further from 0 than -2.

8 0

3 years ago

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How many vertice has a hexagonal pyramid​

How many vertice has a hexagonal pyramid