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3 years ago

What is the actual distance, in miles, between two cities that are 3 inches apart on the map?

Mathematics

1 answer:

frosja888 [35]3 years ago

4 0

Answer:

Step-by-step explanation: to answer this question I need to know what 1 inch to a mile is. like every one inch= 12 miles

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One year Ron had the lowest ERA (earned-run average, mean number of runs yielded per nine innings pitched)

Arada [10]

Answer:

Ron's ERA has a z-score of -2.03.

Karla's ERA has a z-score of -1.86.

Due to the lower z-score, Ron had a better yean than Karla relative to their peers.

Step-by-step explanation:

Z-score:

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this question:

Since the lower the ERA, the better the pitcher, whoever's ERA has the lower z-score had the better year relative to their peers.

Ron

ERA of 3.06, so $X = 3.06$

For the males, the mean ERA was 5.086 and the standard deviation was 0.998. This means that $\mu = 5.086, \sigma = 0.998$

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{3.06 - 5.086}{0.998}$

$Z = -2.03$

Ron's ERA has a z-score of -2.03.

Karla

ERA of 3.28, so $X = 3.28$

For the females, the mean ERA was 4.316 and the standard deviation was 0.558. This means that $\mu = 4.316, \sigma = 0.558$

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{3.28 - 4.316}{0.558}$

$Z = -1.86$

Karla's ERA has a z-score of -1.86.

Which player had the better year relative to their peers, Ron or Karla?

Due to the lower z-score, Ron had a better yean than Karla relative to their peers.

5 0

3 years ago

PLEASE HELP!!!!!!!!!!!!!!!!!!!!!

ivann1987 [24]

1 + 1x
"the sum of one and" 1 +
"the product of" x
"one" 1 x
"and a number x" 1 x (x)
1 + 1x

8 0

3 years ago

What is 76.3 rounded to the nearest whole number

MatroZZZ [7]

76.
If the number after the decimal is below five, you round down. If the number is above five, you round up. 76 is your answer.

6 0

3 years ago

What is d if <img src="https://tex.z-dn.net/?f=%5Cfrac%7B3d-2%7D%7B8%7D%20%3D%20-d%2B16%5Cfrac%7B1%7D%7B4%7D" id="TexFormula1" t

Harlamova29_29 [7]

Answer: d=12

Step-by-step explanation:

$\displaystyle\\\frac{3d-2}{8} =-d+16\frac{1}{4} \\\\\frac{3d-2}{8} =-d+\frac{16*4+1}{4} \\\\\frac{3d-2}{8} =-d+\frac{64+1}{4} \\\\\frac{3d-2}{8} =-d+\frac{65}{4}$

Multiply both parts of the equation by 8:

$\displaystyle\\3d-2=(-d+\frac{65}{4} )(8)\\\\3d-2=-8d+65*2\\\\3d-2=-8d+130\\\\3d-2+2=-8d+130+2\\\\3d=-8d+132\\\\3d+8d=-8d+132+8d\\\\11d=132\\$

Divide both parts of the equation by 11:

$d=12$

8 0

1 year ago

Suppose that your business is operating at the 4.5-Sigma quality level. If projects have an average improvement rate of 50% annu

Luda [366]

Answer:

11.75 years

Step-by-step explanation:

If we ignore the fact that "6-sigma" quality means the error rate corresponds to about -4.5σ (3.4 ppm) and simply go with ...

P(z ≤ -6) ≈ 9.86588×10^-10

and

P(z ≤ -4.5) ≈ 3.39767×10^-6

the ratio of these error rates is about 0.000290372. We're multiplying the error rate by 0.5 each year, so we want to find the power of 0.50 that gives this value:

0.50^t = 0.000290372

t·log(0.50) = log(0.00290372) . . . . take logarithms

t = log(0.000290372)/log(0.50) ≈ -3.537045/-0.301030

t ≈ 11.75

It will take about 11.75 years to achieve Six Sigma quality (0.99 ppb error rate).

_____

<em>Comment on Six Sigma</em>

A 3.4 ppm error rate is customarily associated with "Six Sigma" quality. It assumes that the process may have an offset from the mean of up to 1.5 sigma, so the "six sigma" error rate is P(z ≤ (1.5 -6)) = P(z ≤ -4.5) ≈ 3.4·10^-6.

Using that same criteria for the "4.5-Sigma" quality level, we find that error rate to be P(z ≤ (1.5 -4.5)) = P(z ≤ -3) ≈ 1.35·10^-3.

Then the improvement ratio needs to be only 0.00251699, and it will take only about ...

t ≈ log(0.00251699)/log(0.5) ≈ 8.6 . . . . years

5 0

3 years ago