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2 years ago

PLEASE HELP DUE AT 11:59 For the inequality, find two values for r that make the inequality true: -5x<2

Mathematics

2 answers:

Gnesinka [82]2 years ago

4 0

Answer:

b,e

Step-by-step explanation:

-5x -2= 10 false

-5x3=-15 true

-5x-5=25 false

-5x-6=30 false

-5x5=-25 true

jonny [76]2 years ago

3 0

$\large\textbf{Hey there!}$

$\mathbf{-5x < 2}\\\\\huge\textbf{DIVIDE -5 to BOTH SIDES}\\\mathbf{\dfrac{-5}{-5} < \dfrac{2}{-5}}\\\huge\textbf{CANCEL out: }\huge\boxed{\mathbf{\dfrac{-5}{-5}}}\huge\textbf{ because it give you 1}\\\huge\textbf{KEEP: }\huge\boxed{\mathbf{\dfrac{2}{-5}}}\huge\textbf{ because it help what is being}\\\huge\textbf{compared to the x-value}\\\large\textbf{NEW EQUATION: x }\mathbf{ > \dfrac{2}{-5}}\\\\\huge\textbf{SIMPLIFY IT!}$

$\huge\textbf{Thus, your answer is: \boxed{\mathsf{x > - \dfrac{2}{5}}}}\huge\checkmark$

$\large\textbf{Good luck on your assignment \& enjoy your day!}$

<h3>~ $\frak{Amphitrite1040:)}$ </h3>

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1. From a circular sheet of radius 18 cm, two circles of radii 4.5 cm and a rectangle of length 4 cm and breadth 1 cm are remove

telo118 [61]

Area of a circle = PI x r^2

Area of sheet = 22/7 x 18^2 = 1,018.29 square cm.

Area of small circle = 22/7 x 4.5^2 = 63.64 square cm.

There are 2 small circles so total area of the circles are 63.64 x 2 = 127.28 square cm.

Area of rectangle = l x w = 4 x 1 = 4 square cm.

Total area of cutouts = 127.28 + 4 = 131.28 square cm.

Area of sheet left, subtract area of cutouts fro area of sheet:

1018.29 - 131.28 = 887.01 square cm.

Round everything as needed.

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3 years ago

Quadratic Formula to solve the equation x^2- 4x = - 7

mylen [45]

roots of the equation x^2- 4x = - 7 are 2+3i and 2-3i

What are the natures of root of quadratic equation?

Case I: $4ac > b^2$

The roots of the quadratic equation $ax^2 + bx + c = 0$ are real and unequal when a, b, and c are real numbers, a 0, and the discriminant is positive.

Situation II: $b^2$ $-4ac$ =0

The roots and of the quadratic equation $ax^2 + bx + c = 0$ are real and equal when a, b, and c are real numbers, a 0, and the discriminant is zero.

Case III: $b^2$ $-4ac$ <0

The quadratic equation $ax^2 + bx + c = 0$ has roots when a, b, and c are real numbers, a 0, and the discriminant is negative, but these roots are not equal and are not real. We refer to the roots in this instance as fictitious.

Case IV: Perfect square and $b^2 - 4ac > 0$

The roots of the quadratic equation $ax^2 + bx + c = 0$ are real, rational, and unequal when a, b, and c are real numbers, a 0, and the discriminant is positive and perfect square.

Quadratic Formula $x={\frac {-b\pm {\sqrt {b^{2}-4ac}}}{2a}}$