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2 years ago

PLEASE HELP DUE AT 11:59 For the inequality, find two values for r that make the inequality true: -5x<2

Mathematics

2 answers:

Gnesinka [82]2 years ago

4 0

Answer:

b,e

Step-by-step explanation:

-5x -2= 10 false

-5x3=-15 true

-5x-5=25 false

-5x-6=30 false

-5x5=-25 true

jonny [76]2 years ago

3 0

$\large\textbf{Hey there!}$

$\mathbf{-5x < 2}\\\\\huge\textbf{DIVIDE -5 to BOTH SIDES}\\\mathbf{\dfrac{-5}{-5} < \dfrac{2}{-5}}\\\huge\textbf{CANCEL out: }\huge\boxed{\mathbf{\dfrac{-5}{-5}}}\huge\textbf{ because it give you 1}\\\huge\textbf{KEEP: }\huge\boxed{\mathbf{\dfrac{2}{-5}}}\huge\textbf{ because it help what is being}\\\huge\textbf{compared to the x-value}\\\large\textbf{NEW EQUATION: x }\mathbf{ > \dfrac{2}{-5}}\\\\\huge\textbf{SIMPLIFY IT!}$

$\huge\textbf{Thus, your answer is: \boxed{\mathsf{x > - \dfrac{2}{5}}}}\huge\checkmark$

$\large\textbf{Good luck on your assignment \& enjoy your day!}$

<h3>~ $\frak{Amphitrite1040:)}$ </h3>

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Answer:

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Step-by-step explanation:

The equation of curve is

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The point of tangency is (-3,1). It means the slope of tangent is $\frac{dy}{dx}_{(-3,1)}$ .

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Divide both sides by 130.

$\frac{dy}{dx}=\frac{9}{13}$

If a line passes through a points $(x_1,y_1)$ with slope m, then the point slope form of the line is

$y-y_1=m(x-x_1)$

The slope of tangent line is $\frac{9}{13}$ and it passes through the point (-3,1). So, the equation of tangent is

$y-1=\frac{9}{13}(x-(-3))$

$y-1=\frac{9}{13}(x)+\frac{27}{13}$

Add 1 on both sides.

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$y=\frac{9}{13}(x)+\frac{40}{13}$

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