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3 years ago

11

Draw and label a coordinate plane, including the four quadrants and the positive or negative values of x and y in each quadrant.

pls help

2 answers:

tangare [24]3 years ago

7 0

Hey how you doing, you know school sucks

Nimfa-mama [501]3 years ago

3 0

Answer:

the answer is c

Step-by-step explanation:

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What is the value of the expression 6 3/4 ( -11.5)?

emmasim [6.3K]

Answer:

I'm assuming your problem looks like this: 4+5*6-3 =? To solve this problem you need to use the order of operations. PEMDAS which stands for Parentheses, exponents, multiply and divide, and lastly add and subtract. You must multiply and divide before you add and subtract so you must do 5*6 first. You now get 4+30-3. Now all you have left is addition and subtraction so you now just go from right to left and do one at a time. So 4+30 = 34 , 34-3=31. Therefore your answer should be 31. Hope that helped!

Step-by-step explanation:

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2 years ago

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frutty [35]

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2 years ago

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Given that sec theta= -37/12, what is the value of cot theta , for pie/2 < theta< pie?

Triss [41]

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3 years ago

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Multiply. (2x2 + 4x - 3)(x2 - 2x + 5)

BigorU [14]

For a moment, let $y=x^2-2x+5$ . Then by the distributive property,

$(2x^2+4x-3)p=2x^2p+4xp-3p$

Again by the distributive property,

$2x^2p=2x^2(x^2-2x+5)=2x^4-4x^3+10x^2$

$4xp=4x(x^2-2x+5)=4x^3-8x^2+20x$

$-3p=-3(x^2-2x+5)=-3x^2+6x-15$

Taking everything together, we get

$(2x^2+4x-3)(x^2-2x+5)=(2x^4-4x^3+10x^2)+(4x^3-8x^2+20x)+(-3x^2+6x-15)$
$(2x^2+4x-3)(x^2-2x+5)=2x^4-x^2+26x-15$

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3 years ago

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salantis [7]

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2 years ago