Answer:
Step-by-step explanation:
Given that a basketball coach will select the members of a five-player team from among 9 players, including John and Peter.
Out of nine players five are chosen at random.
The team consists of John and Peter.
Hence we can sort 9 players as I group, John and Peter and II group 7 players.
Now the selection is 2 from I group and remaining 3 from II group.
Hence no of ways of selecting a team that includes both John and Peter=
=35
Total no of ways =
=126
=
=
Whats the question ill be happy to help
It would be lines that are plane and line
16. 4 (9*4=36)
17. 6 (6*11=66)
18. 8 (10*8=80)
19. 9 (9*5=45)
20. 48 (4*12=48)
21. 13 (13*2=26)
F(x)=(x-10)^2
Right is negative
Left is positive
Remember that - those become handy later on. Try to become really good at transformations!
Good luck!