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3 years ago

Can someone please help me? I need to find the equation.

Mathematics

1 answer:

amm18123 years ago

5 0

You've already found the rule for the table.

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5(8k + 9m) simplified expression

Firdavs [7]

Answer:

40k+45m

Step-by-step explanation:

5(8k)=40k + 5(9m)= 45m

8 0

3 years ago

Which of the following is a solution to the inequality y < –2x + 3?

Karo-lina-s [1.5K]

The best answer is A

8 0

3 years ago

HELP ME!! im so stumped. will give brainliest!

Olegator [25]

Answer:

$x=1+\sqrt{3}$ and $x=1-\sqrt{3}$

Step-by-step explanation:

We have been given the parabola with vertex (1, -9) and y intercept at (0, -6).

Now we need to find the x-intercepts of that parabola. So first we begin by finding the equation of parabola using vertex formula:

$y=a\left(x-h\right)^2+k$

Vertex for this formula is given by (h,k)

Compare that with given vertex (1,-9), we get: h=1, k=-9

So plug these into vertex formula:

$y=a\left(x-1\right)^2-9$ ...(i)

Plug given point (0, -6). into (i)

$-6=a\left(0-1\right)^2-9$

$-6=a\left(-1\right)^2-9$

$-6=a\left(1\right)-9$

$-6+9=a$

$3=a$

Plug a=3 into (i)

$y=3\left(x-1\right)^2-9$

Now to find x-intercept, we just plug y=0 and solve for x

$y=3\left(x-1\right)^2-9$

$0=3\left(x-1\right)^2-9$

$9=3\left(x-1\right)^2$

$3=\left(x-1\right)^2$

$\pm \sqrt{3}=x-1$

$1+\pm \sqrt{3}=x$

Hence final answer are

$x=1+\sqrt{3}$ and $x=1-\sqrt{3}$

4 0

3 years ago

How do you solve 6<_2g?

horrorfan [7]

Divide both sides by 2 to isolate variable g.

You're left with 6 / 2 < g which equals 3 < g.

3 0

3 years ago

An article fills 5/8 of a magazine page. A related photo takes 1/4 of the article. How much of the page is taken up by the photo

kirza4 [7]

Answer:

2/8

Step-by-step explanation:

6 0

2 years ago