$\frac{1}{10}+\frac{1}{4}+\frac{1}{5}+\frac{2}{15}= \\ \\ \frac{1 \times 6}{10 \times 6}+\frac{1 \times 15}{4 \times 15}+\frac{1 \times 12}{5 \times 12}+\frac{2 \times 4}{15 \times 4}= \\ \\
\frac{6}{10}+\frac{15}{60}+\frac{12}{60}+\frac{8}{60}= \\ \\ \frac{41}{60}$

The answer is A.

4 0

3 years ago

I need to solve for b but I don't know how

lorasvet [3.4K]

It base times height

5 0

3 years ago

What would be the final elevation if a moth is flying at at 9 meters above the ground and changes by -4?

quester [9]

5 because this is equivalent to 9-4 which is 5 meters, this is because he is going up 9 and then goes down 4, do 9-4, which is 5

6 0

3 years ago

The graph below shows the solution to which system of inequalities?

nlexa [21]

Answer:

Option D.

Step-by-step explanation:

Consider option D. $y\leq \frac{3x}{4}+10\,,\,y\leq \frac{-x}{2}-3$

Take point (0,0)

On putting this point in inequation $y\leq \frac{3x}{4}+10$ , we get

$0\leq 10$ which is true . So, solution is region towards the origin i,e region below the line $y= \frac{3x}{4}+10$ including the line itself .

On putting (0,0) in inequation $y\leq \frac{-x}{2}-3$ , we get $0\leq -3$ which is false , so solution is region away from the origin i.e region below line $y= \frac{-x}{2}-3$ including the line itself .

So, common solution to both the inequations is the shaded part in the given figure .

In other words, we can say that the graph shown in the given figure represents system of equations: $y\leq \frac{3x}{4}+10\,,\,y\leq \frac{-x}{2}-3$

5 0

3 years ago