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3 years ago

I NEED HELP REALLY FAST!!!! PLEASE!!!!

Mathematics

2 answers:

Maru [420]3 years ago

4 0

I think it is B hope it is right

Andrei [34K]3 years ago

4 0

A) 0.238095 there all the same but there right

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MathsWatch Question Please Help

seraphim [82]

Make sure you make me brainest

8 0

2 years ago

Find an equation of the plane orthogonal to the line

jolli1 [7]

The given line is orthogonal to the plane you want to find, so the tangent vector of this line can be used as the normal vector for the plane.

The tangent vector for the line is

d/dt (⟨0, 9, 6⟩ + ⟨7, -7, -6⟩t ) = ⟨7, -7, -6⟩

Then the plane that passes through the origin with this as its normal vector has equation

⟨x, y, z⟩ • ⟨7, -7, -6⟩ = 0

We want the plane to pass through the point (9, 6, 0), so we just translate every vector pointing to the plane itself by adding ⟨9, 6, 0⟩,

(⟨x, y, z⟩ - ⟨9, 6, 0⟩) • ⟨7, -7, -6⟩ = 0

Simplifying this expression and writing it standard form gives

⟨x - 9, y - 6, z⟩ • ⟨7, -7, -6⟩ = 0

7 (x - 9) - 7 (y - 6) - 6z = 0

7x - 63 - 7y + 42 - 6z = 0

7x - 7y - 6z = 21

so that

a = 7, b = -7, c = -6, and d = 21

4 0

3 years ago

After spending some time looking for his pump, Marlon pumps up an uninflated balloon, pumping air into it at a constant rate. He

galina1969 [7]

Answer:

Graph D

Step-by-step explanation:

Initially, Marlon was looking for his pump. Thus, no air was pumped into the balloon until he got the pump. On getting the pump, he inflated the balloon with air at a constant rate, after which he tied it with a string to prevent the air from escaping.

The analysis is that, at the time he decided to inflate the balloon till he got a pump, the volume of air in the balloon is zero with respect to time. Pumping air at a steady rate into the balloon increases the volume of air flowing into it gradually and steadily.

When the volume got to a definite amount, he stopped pumping air and tied with a string. Thus, the volume of air in the balloon remains constant.

8 0

2 years ago

What is the value of x? x + 13 = 59

Volgvan

Answer:

x=46

Step-by-step explanation:

subtract 13 from both sides

x=59-13=46

7 0

3 years ago

PLEASE HELP ASAP!!!

EleoNora [17]

Part 1:

$(x+1)^2-3(x+2) \\ \\ =x^2+2x+1-3x-6 \\ \\ =x^2-x-5$

option b.

Part 2:
$(5x^3y^{-3})(-6x^4y)\\ \\=5(-6)x^{3+4}y^{-3+1}\\ \\=-30x^7y^{-2}\\ \\=\frac{-30x^7}{y^2}$

option d

Part 3:
$\frac{8+x}{2} - \frac{x+3}{3} =4$

Multiply through by the LCM of 2 and 3 (i.e. 6)
$6\left(\frac{8+x}{2}\right) - 6\left(\frac{x+3}{3}\right) =6(4) \\ \\ 3(8+x)-2(x+3)=24 \\ \\ 24+3x-2x-6=24 \\ \\ x+18=24 \\ \\ x=24-18=6$

option b

Part 4
x^2-3x-8=x+4

$x^2-3x-8=x+4 \\ \\ x^2-3x-x-8-4=0 \\ \\ x^2-4x-12=0 \\ \\ (x-6)(x+2)=0 \\ \\ x=6 \ or \ -2$

option d

Part 5
Joseph is solving the equation x^2+8x-4=0 using the technique completing the square.
x^2+8x-4=0
x^2+8x+?=4+?

In completeing the square method, you divide the coeficient of x by 2, square the result and add to both sides of the equation.

Therefore, he should add 16 to both sides because (8/2)^2=16.

option d.

5 0

2 years ago