Will a large-sample confidence interval be valid if the population from which the sample is taken is not normally distributed? e
1 answer:
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<h3>Answer:</h3>
- 1st equation: x + 2y = 50
- 2nd equation: x - 2y = 130
- x + 2y = 50
- x = 50 - 2y
- (50 - 2y) - 2y = 130
- 50 - 2y - 2y = 130
- -4y = 130 - 50
- -4y = 80
- y = -20
- x = 50 - 2y
- x = 50 - 2(-20)
- x = 90
- x - (y)
- 90 - (-20)
- 110
Answer:
Median = 8
Step-by-step explanation:
Data set representing the number of bushes in the yards of the houses in the neighborhood will be,
{5, 5, 6, 6, 6, 7, 7, 7, 7, 8, 8, 8, 9, 9, 10, 11, 11, 11, 11, 11}
Total number of houses = 20
Since, 20 is an even number,
Median of the data = average of middle two term
= average of 20th term and 21st term of the data set
=
= 8
Median of the data set = 8