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Murljashka [212]

2 years ago

14

Explain your answer !! Have a nice day Will give braisnlt

2 answers:

yan [13]2 years ago

8 0

Answer: x=3, y=4

Step-by-step explanation:

We are going to use the elimination method to solve this since the x values have inverse of each other. We are going to add the 2nd equation to the 1st and we will get: y=-4 then plug y=-4 into one of the equations, then solve for x. 4(x)+5(-4)=-8, 4x-20=-8, 4x=12, x=3. So x=3, y=4

nikdorinn [45]2 years ago

3 0

Answer: x=3, y=-4

Step-by-step explanation:

First, get either the x or the y variable by itself using one of the given equations:

-4x-4y=4

-4y=4+4x

y=-(4+4x)/4

y=-1-x

Then plug this into all the y variable in the other equation to find x:

4x+5(-1-x)=-8

4x-5-5x=-8

-1x-5=-8

-x=-3

x=3

Then plug this into ever x of one of the equations to find y:

4(3)+5y=-8

12+5y=-8

5y=-20

y=-4

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julsineya [31]

Answer:

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Step-by-step explanation:

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7 0

3 years ago

A purse originally cost $45.99. This week, it is on sale for 25% off.

sertanlavr [38]

Answer: A

Step-by-step explanation:

8 0

2 years ago

Read 2 more answers

Solve the inequality.

marysya [2.9K]

Answer:

$\huge x > \frac{7}{3} \\$

Step-by-step explanation:

$8( \frac{1}{2} x - \frac{1}{4} ) > 12 - 2x \\$

<u>Expand the terms in the bracket</u>

That's

$8( \frac{1}{2} x) - 8( \frac{1}{4} ) > 12 - 2x \\ 4x - 2 > 12 - 2x$

Move -2x to the other side of the inequality

$4x + 2x - 2 > 12 \\ 6x - 2 > 12$

<u>Move - 2 to the other side of the inequality</u>

$6x > 12 + 2 \\ 6x > 14$

Divide both sides by 6

$\frac{6x}{6} > \frac{14}{6} \\$

We have the final answer as

$x > \frac{7}{3} \\$

Hope this helps you

5 0

3 years ago

Find the inverse of the function. y = x2 + 4x + 4

QveST [7]

Factors of 4: 2 and 2
y= (x+2)²
+√y or -√y = x+2

x= 2+√y , 2-√y

interchange variables
y= 2+√x , 2-√x

f ⁻¹(x) = 2 + √x, 2 - √x

8 0

3 years ago

Read 2 more answers

I only really need the domain and range, intervals, and end behavior. My Precalculus class never covered piecewise functions so

Serjik [45]

(a)

Domain:

we know that domain is all possible values of x for which any function ios defined

Here, curve is defined for all values of x

so, domain is

$(-\infty,\infty)$

Range:

Range is all possible values of y for which x is defined

minimum value of y is -4

maximium value of y is +inf

so, range is

$[-4,\infty)$

(b)

x-intercept:

It is the value of x where f(x)=0

so, the point where curve intersects on x-axis

and we get

$2x^2-4=0$

$x=\sqrt{2}$

and

$x=-5$

(c)

Increasing interval:

where curve is moving upward

we can see that

$(0,\infty)$

Decreasing interval:

where curve is moving downward

we get

$(-\infty,-1)U(-1,0)$

Constant:

constant means horizontal line

there is no horizontal line here

so, it does not exist

(D)

End behavior:

when x-->+inf

y is moving upward

so, y---->+inf

when x-->-inf

y is moving upward

so, y---->+inf

(E)

we can see that curve jupms at x=-1

so, there is discontinuity at x=-1

and this is jump type of discontinuity

(F)

For odd:

f(-x)=-f(x)

For even:

f(-x)=f(x)

we can see that none of them holds true

so, this is neither

3 0

3 years ago