There 7 blocks of hundreds which means each such block is equivalent to 100.
There are 5 blocks of tens, which means each such block is equivalent to 10.
There are 8 blocks of ones, which means each such block is equivalent to 1.
The total of these blocks will be = 7(100) + 5(10) + 8(10) = 758
We can make several two 3-digit numbers from these blocks. An example is listed below:
Example:
Using 3 hundred block, 2 tens blocks and 4 ones block to make one number and remaining blocks to make the other number. The remaining blocks will be 4 hundred blocks, 3 tens blocks and 4 ones blocks
The two numbers we will make in this case are:
1st number = 3(100) + 2(10) + 4(1) = 324
2nd number = 4(100) + 3(10) + 4(1) = 434
The sum of these two numbers is = 324 + 434 = 758
i.e. equal to the original sum of all blocks.
This way changing the number of blocks in each place value, different 3 digit numbers can be generated.
Answer:
486
Step-by-step explanation:
for the 2nd term, add 5 to -9
for the 3rd, add 5 × 2 to -9
for the 4th, add 5 × 3 to -9
:
for the 100th, add 5 × (100 - 1) to -9
=> 5 × 99 + (-9)
=> 486
Answer:
Step-by-step explanation:
Given
Required
Find x
We have:
Rewrite as:
Expand
Factorize
Factor out x + 520
Split
Solve
Side length must be positive;
So:
Answer:
The value is Approximately 56
