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Murljashka [212]
2 years ago
14

Explain your answer !! Have a nice day Will give braisnlt

Mathematics
2 answers:
yan [13]2 years ago
8 0

Answer: x=3, y=4

Step-by-step explanation:

We are going to use the elimination method to solve this since the x values have inverse of each other. We are going to add the 2nd equation to the 1st and we will get: y=-4 then plug y=-4 into one of the equations, then solve for x.   4(x)+5(-4)=-8, 4x-20=-8, 4x=12,  x=3. So x=3, y=4

nikdorinn [45]2 years ago
3 0

Answer: x=3, y=-4

Step-by-step explanation:

First, get either the x or the y variable by itself using one of the given equations:

-4x-4y=4

-4y=4+4x

y=-(4+4x)/4

y=-1-x

Then plug this into all the y variable in the other equation to find x:

4x+5(-1-x)=-8

4x-5-5x=-8

-1x-5=-8

-x=-3

x=3

Then plug this into ever x of one of the equations to find y:

4(3)+5y=-8

12+5y=-8

5y=-20

y=-4

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Hoochie [10]

Answer:

For part 1- y=50x+75 For part 2- y=325

Step-by-step explanation:

the cost is increasing 50 for every hour

there is a flat rate of 75 to answer a house call

y=50x+75

y=50(5)+75

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3 years ago
Prove that:
devlian [24]

Answer:

<u>Identities used:</u>

  • <em>1/cosθ = secθ</em>
  • <em>1/sinθ = cosecθ</em>
  • <em>sinθ/cosθ = tanθ</em>
  • <em>cosθ/sinθ = cotθ</em>
  • <em>sin²θ + cos²θ = 1</em>
<h3>Question 1 </h3>
  • (1 - sinθ)/(1 + sinθ) =        
  • (1 - sinθ)(1 - sinθ) / (1 - sinθ)(1 + sinθ) =
  • (1 - sinθ)² / (1 - sin²θ) =
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<u>Square root of it is:</u>

  • (1 - sinθ)/ cosθ =
  • 1/cosθ - sinθ / cosθ =
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<h3>Question 2 </h3>

<u>The first part without root:</u>

  • (1 + cosθ) / (1 - cosθ) =
  • (1 + cosθ)(1 + cosθ) / (1 - cosθ)(1 + cosθ)
  • (1 + cosθ)² / (1 - cos²θ) =
  • (1 + cosθ)² / sin²θ

<u>Its square root is:</u>

  • (1 + cosθ) / sinθ =
  • 1/sinθ + cosθ/sinθ =
  • cosecθ + cotθ

<u>The second part without root:</u>

  • (1 - cosθ) / (1 + cosθ) =
  • (1 - cosθ)²/ (1 + cosθ)(1 - cosθ) =
  • (1 - cosθ)²/ (1 - cos²θ) =
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<u>Its square root is:</u>

  • (1 - cosθ) / sinθ =
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<u>Sum of the results:</u>

  • cosecθ + cotθ + cosecθ - cotθ =
  • 2cosecθ
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