hello ....
the equation of a plane that is ; ax+by+cz +d =0
the vector perpendicular to this plane is : V(a,b,c)
in this exercice ; a = -4 b= -4 c = -1
then: the equation of a plane that is ; -4x-4y-z +d =0
but the plane passing through the point (−2,−5,5) :
-4(-2)-4(-5)-(5) +d =0
23+d =0
d =-23
the equation of a plane is : -4x-4y-z-23 =0
Answer:
see explanation
Step-by-step explanation:
Since XY bisects ∠ WXZ then ∠ WXY = ∠ YXZ , thus
7x - 7 = 5x + 3 ( subtract 5x from both sides )
2x - 7 = 3 ( add 7 to both sides )
2x = 10 ( divide both sides by 2 )
x = 5
(b)
∠ WXY = 7x - 7 = 7(5) - 7 = 35 - 7 = 28°
(c)
∠ YXZ = 5x + 3 = 5(5) + 3 = 25 + 3 = 28°
(d)
∠ WXZ = ∠ WXY + ∠ YXZ = 28° + 28° = 56°
Answer:
46
Step-by-step explanation:
(32 + 90 + 92 + 82 + 64 + x) / 6 = 85
(360 + x) / 6 = 85
360 + x = 85 * 6
360 + x = 510
x = 510 - 360
x = 150 <===
