two years ago, paul was 7 times as old as matt was. two year from now, paul will be five times as old as matt will be. find the

Question

2 years ago

6

present age of each

1 answer:

Sliva [168] · Answer 1 · 2023-06-23T10:55:03+03:00

The present age of Paul is 52 years and the present age of Matt is 10 years.

We are given that two years ago, Paul = 7 times as Matt

Let the current age of Matt be x and of Paul be y

2 years ago, we will have that:

Age of Matt = x - 2

So, we get the equation as:

Age of Paul = 7 ( x - 2) = 7 x - 14

y - 2 = 7 x - 14

y = 7 x - 14 + 2

y = 7 x - 12

Also, we are given that to year from now, Paul = five times Matt

We get that:

y + 2 = 5 ( x + 2)

y + 2 = 5 x + 10

y = 5 x + 10 - 2

y = 5 x + 8

So, we get:

7 x - 12 = 5 x + 8

7 x - 5 x = 8 + 12

2 x = 20

x = 20 / 2

x = 10

y = 5 (10) + 2

y = 50 + 2

y = 52

Therefore, the present age of Paul is 52 years and the present age of Matt is 10 years.

Learn more about equation here:

#SPJ4