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Lady_Fox [76]
1 year ago
15

0.38 as a mixed number​

Mathematics
1 answer:
Katena32 [7]1 year ago
5 0
0.38 is a mixed number could be variables of 0.00
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Consider the following argument: If pigs have wings, then pigs can fly. If pigs are lighter than air, then pigs can fly. Pigs ha
Darina [25.2K]

Answer:

a ) If r ⇒ p

    If q ⇒ p

    r ∪ q

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   ∴ s

b) The argument is invalid

Step-by-step explanation:

The argument is invalid because we do not with precision if b), because we do not have enough information about it, and this is because the previous sentences does not mention information about the donkey. We cannot infer something when we do not have enough information.

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3 years ago
The volume of rectangular bar is 640 cubic units. The width is 3 units more than the height and the length is 1 unit more than t
ASHA 777 [7]

Answer:

H = 5 , W = 8 , L = 16

Step-by-step explanation:

6 0
1 year ago
1 1/5 divided by 2/3?
Goryan [66]
The answer should be 1.8 or 1 4/5
8 0
3 years ago
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A triangle has side lengths of (1.3k+3.5m)(1.3k+3.5m) centimeters, (4.1k-1.6n)(4.1k−1.6n) centimeters, and (9.7n+4.4m)(9.7n+4.4m
Scorpion4ik [409]

Answer:

(5.4k+7.9m+8.1n) centimeters

Step-by-step explanation:

Given the side length of a triangle;

S1 = (1.3k+3.5m) cm

S2 = (4.1k-1.6n) cm

S3 = (9.7n+4.4m) cm

Perimeter of the triangle = S1+S2 + S3

Perimeter of the triangle = (1.3k+3.5m) + (4.1k-1.6n) + (9.7n+4.4m)

Collect the like terms;

Perimeter of the triangle = 1.3k+4.1k+3.5m+4.4m-1.6n+9.7n

Perimeter of the triangle = 5.4k+7.9m+8.1n

Hence the expression that represents the perimeter of the triangle is (5.4k+7.9m+8.1n) centimeters

5 0
3 years ago
Solve the system of linear equations below.
Olegator [25]

Answer:

B. x = 2, y = 6

Step-by-step explanation:

2x + 5y = 34...(1) \\  \\ x + 2y = 14 \\  \therefore \: x = 14 - 2y...(2) \\  \\ from \: equations \: (1) \: and \: (2) \\  \\ 2(14 - 2y) + 5y = 34 \\ \therefore \: 28 - 4y + 5y = 34 \\  \therefore \: 28 + y = 34 \\ \therefore \:  y = 34 - 28 \\  \huge \red{ \boxed{\therefore \:  y = 6}} \\ substituting \: y = 6 \: in \: equation \: (2) \\ x = 14 - 2 \times 6 \\ \therefore \:  x =14 - 12 \\  \huge \purple{ \boxed{\therefore \:  x =2}} \\  \\ \huge \orange{ \boxed{ \therefore \:  x  = 2, \:  \: y = 6}} \\

5 0
3 years ago
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