Answer:
The value of Car B will become greater than the value of car A during the fifth year.
Step-by-step explanation:
Note: See the attached excel file for calculation of beginning and ending values of Cars A and B.
In the attached excel file, the following are used:
Annual Depreciation expense of Car A = Initial value of Car A * Depreciates rate of Car A = 30,000 * 20% = 6,000
Annual Depreciation expense of Car B from Year 1 to Year 6 = Initial value of Car B * Depreciates rate of Car B = 20,000 * 15% = 3,000
Annual Depreciation expense of Car B in Year 7 = Beginning value of Car B in Year 7 = 2,000
Conclusion
Since the 8,000 Beginning value of Car B in Year 5 is greater than the 6,000 Beginning value of Car A in Year 5, it therefore implies that the value Car B becomes greater than the value of car A during the fifth year.
Answer:
18x+36
Step-by-step explanation:
9(2x+6) - 18
Distribute
9*2x + 9 *6 -18
18x +54 -18
Combine like terms
18x+36
Answer:
8 interior angles
Step-by-step explanation:
- There is a simple trick to finding the number of interior angles
- For instance, a triangle has 3 sides, and how many angles are in a triangle? 3
- A square has 4 sides and 4 interior angles
- A pentagon has 5 sides and 5 interior angles
- So an octagon, the shape we have here, has 8 sides so 8 interior angles
Hi,
A)

B)
Only if n=4*k or n=4*k+1 , k beeing an integer.