Choose the equation that represents a line that passes through points (−1, 2) and (3, 1).
2 answers:
Answer:
the equation of this line is y = (-1/4)x + 7/4
Step-by-step explanation:
As we go from (−1, 2) to (3, 1), x increases by 4 and y decreases by 1. Thus, the slope of the line connecting these points is m = rise / run = -1/4.
Find the equation of this line in slope-intercept form, y = mx + b. Substitute 1 for y and 3 for x and calculate b:
1 = (-1/4)(3) + b, or
4/4 = -3/4 + b, or
7/4 = b.
Then the equation of this line is y = (-1/4)x + 7/4 .
You did not provide us with equations to select.
Find the slope m.
m = (1 - 2)/(3 - (-1))
m = -1/(3 + 1)
m = -1/4
Use the slope and one of the points and plug into the point-slope formula.
y - 1 = (-1/4)(x - 3)
Isolate y.
y - 1 = (-1/4)x + (3/4)
y = (-1/4)x + (3/4) + 1
y = (-1/4)x + (7/4)
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