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1 year ago

as a contractor to make a hole 4 5/8 inches diameter. express the mixed number as an improper fraction.

Mathematics

1 answer:

san4es73 [151]1 year ago

7 0

The mixed number as an improper fraction is 37/8

<h3>How to express the mixed number as an improper fraction?</h3>

The diameter is give as:

Diameter = 4 5/8

Next we convert the above number to an improper fraction

The numerator is calculated as

Numerator = 8 * 4 + 5

This gives

Numerator = 37

Hence, the mixed number as an improper fraction is 37/8

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Evaluate ∫ xe2x dx. 1 2 3x A./xe +C 6 B.1/xe2x-1/ xe2x+C 22 C.1/xe2x-1/ e2x+C 24 1 2 1 4x D./x-/e +C 28

Dafna1 [17]

The answer is (1/2)xe^(2x) - (1/4)e^(2x) + C

Solution:
Since our given integrand is the product of the functions x and e^(2x), we can use the formula for integration by parts by choosing
u = x
dv/dx = e^(2x)

By differentiating u, we get
du/dx= 1
By integrating dv/dx= e^(2x), we have
v =∫e^(2x) dx = (1/2)e^(2x)

Then we substitute these values to the integration by parts formula:
∫ u(dv/dx) dx = uv −∫ v(du/dx) dx
∫ x e^(2x) dx = (x) (1/2)e^(2x) - ∫ ((1/2) e^(2x)) (1) dx
= (1/2)xe^(2x) - (1/2)∫[e^(2x)] dx
= (1/2)xe^(2x) - (1/2) (1/2)e^(2x) + C
where c is the constant of integration.

Therefore,
∫ x e^(2x) dx = (1/2)xe^(2x) - (1/4)e^(2x) + C

7 0

3 years ago

Solve the following system of equations. Write each of your answers as a fraction reduced to lowest terms. In other words, write

morpeh [17]

Answer:

x = 57/28

y = -95/84

z = 97/168

Step-by-step explanation:

Use the application in the next link: https://www.zweigmedia.com/RealWorld/tutorialsf1/scriptpivotold.html

Start with the expanded array:

$\left[\begin{array}{cccc}1&5&8&1\\3&2&2&5\\-2&-7&2&5\\\end{array}\right]$

then using the tool provided, make row operations until you find the solution:

r2 = r2-3r1

$\left[\begin{array}{cccc}1&5&8&1\\0&-13&-22&2\\-2&-7&2&5\\\end{array}\right]$

r3 = r3+2r1

$\left[\begin{array}{cccc}1&5&8&1\\0&-13&-22&2\\0&3&18&7\\\end{array}\right]$

r2 = r2*(-1/13)

$\left[\begin{array}{cccc}1&5&8&1\\0&1&22/13&-2/13\\0&3&18&7\\\end{array}\right]$

r1 = r1- r2*5

$\left[\begin{array}{cccc}1&0&-6/13&23/13\\0&1&22/13&-2/13\\0&3&18&7\\\end{array}\right]$

r3 = r3+ r2*-3

$\left[\begin{array}{cccc}1&0&-6/13&23/13\\0&1&22/13&-2/13\\0&0&168/13&97/13\\\end{array}\right]$

r3 = r3*13/168

$\left[\begin{array}{cccc}1&0&-6/13&23/13\\0&1&22/13&-2/13\\0&0&1&97/168\\\end{array}\right]$

r2 = r2- r3*22/13

$\left[\begin{array}{cccc}1&0&-6/13&23/13\\0&1&0&-95/84\\0&0&1&97/168\\\end{array}\right]$

r2 = r2+ r3*6/13

$\left[\begin{array}{cccc}1&0&0&57/28\\0&1&0&-95/84\\0&0&1&97/168\\\end{array}\right]$

Here you have a reduced array an therefore the answers to each variable are on each row:

$\left[\begin{array}{c}x\\y\\z\end{array}\right]$

8 0

3 years ago

Carlos needs 1.7 meters of wire for one project and 0.8 meters of wire for another project shade the model to represent the tota

vesna_86 [32]

Answer:

Step-by-step explanation:

Given that ;

Carlos needs 1.7 meters of wire for one project &

0.8 meters of wire for another project

we are to shade the model to represent the total amount of wire Carlos needs .

NOW;

For both projects ; Carlos needs ( 1.7 + 0.8) meters of wire = 2.5 meters of wire

In the attached files below. the first picture shows the diagram attached to the question and the second one shows the shading of the model which represent the total amount of wire Carlos needs.

7 0

3 years ago

Can someone please help me with this?

Art [367]

Answer:

1. $0.34

2. .8

Step-by-step explanation:

8 0

2 years ago

Read 2 more answers

Select Yes or No to indicate whether each value of x is a solution to the given equation.

AlexFokin [52]

Answer:

x = -2 YES

x = 1 NO

x = 2 YES

Step-by-step explanation:

Hope this helps <3

5 0

3 years ago