The answer would be A. -18x^7
hope this helps:)
Answer:
(a)3
(b)4
(c)6
(d)5
Step-by-step explanation:
(a)Josie rolls a six-sided die 18 times.
P(she rolls a two)=1/6
Therefore, the estimated number of times she rolls a two in 18 trials
=1/6 X 18
=3
(b)Slips of paper are numbered 1 through 10.
P(the number 10 appear)=1/10
If one slip is drawn and replaced 40 times, expected number of 10
=1/10 X 40
=4
(c)A spinner consists of 10 equal- sized spaces: 2 red, 3 black, and 5 white.
P(red)=2/10
If the spinner is spun 30 times, expected number of red space
=2/10 X 30
=6
(d)A card is picked from a standard deck
P(drawing an ace)=4/52
If the card is picked 65 times and replaced each time.
Expected Number of Aces =4/52 X 65 =5
In this question, we are given a matrix, and we have to perform the given operation.
The matrix is:
![\left[\begin{array}{ccc}6&-1&|5\\1&-5&|0\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D6%26-1%26%7C5%5C%5C1%26-5%26%7C0%5Cend%7Barray%7D%5Cright%5D)
The following operation is given:

In which
is the element at the first line and
is the element at the second line.
Updating the first line:



Thus, the filled matrix will be given by:
![\left[\begin{array}{ccc}0&29&|5\\1&-5&|0\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D0%2629%26%7C5%5C%5C1%26-5%26%7C0%5Cend%7Barray%7D%5Cright%5D)
For another example where row operations are applied on a matrix, you can check brainly.com/question/18546657
The answer is, in order, -4.5, and -4.375
Answer:
She must consider 3507 components to be 90% sure of knowing the mean will be within ± 0.1 mm.
Step-by-step explanation:
We are given that an engineer wishes to determine the width of a particular electronic component. If she knows that the standard deviation is 3.6 mm.
And she considers to be 90% sure of knowing the mean will be within ±0.1 mm.
As we know that the margin of error is given by the following formula;
The margin of error =
Here,
= standard deviation = 3.6 mm
n = sample size of components
= level of significance = 1 - 0.90 = 0.10 or 10%
= 0.05 or 5%
Now, the critical value of z at a 5% level of significance in the z table is given to us as 1.645.
So, the margin of error =
0.1 mm = 

= 59.22
n =
= 3507.0084 ≈ 3507.
Hence, she must consider 3507 components to be 90% sure of knowing the mean will be within ± 0.1 mm.