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joja [24]
3 years ago
10

If cos A = 1/2, then what is the positive value of cos 1/2 A, in simplest radical form with a rational denominator?

Mathematics
1 answer:
stepan [7]3 years ago
3 0

Answer:

\cos(\frac{1}{2}A) = {\frac{\sqrt{3}}{2}

Step-by-step explanation:

Given

\cos A = \frac{1}{2}

Required

Determine \cos(\frac{1}{2}A)

To do this, we make use of the following identity

\cos(\frac{1}{2}A) = \sqrt{\frac{\cos A+1}{2}}

Substitute: \cos A = \frac{1}{2}

\cos(\frac{1}{2}A) = \sqrt{\frac{\frac{1}{2}+1}{2}}

Solve the numerator

\cos(\frac{1}{2}A) = \sqrt{\frac{\frac{2+1}{2}}{2}}

\cos(\frac{1}{2}A) = \sqrt{\frac{\frac{3}{2}}{2}}

Rewrite as:

\cos(\frac{1}{2}A) = \sqrt{\frac{3}{2} * \frac{1}{2}}

\cos(\frac{1}{2}A) = \sqrt{\frac{3}{4}}

Take square roots

\cos(\frac{1}{2}A) = {\frac{\sqrt{3}}{2}

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Answer:

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Step-by-step explanation:

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8 0
3 years ago
Tonya and Pearl each completed a separate proof to show that alternate interior angles AKL and FLK are congruent. Who completed
zalisa [80]

Answer:

Tonya proof is correct
and Pearl proof is wrong

Step-by-step explanation:

AKL and GKB are obviously congruent. But the reasons given are different, One of the justification is Vertical Angles Theorem, and the other is Adjacent Angles.

But the correct justification is the Vertical Angles Theorem, because the angles are Vertically away from each other, or the angles are at opposite sides of each other. Which is when Vertical Angles Theorem is applied.
Making Tonya correct since that was the answer he given.

The definition of Adjacent Angles is incorrect, this Theorem is used when the angles are Adjacent to each other. When the angles are on the same line as the other angle, is when the definition of Adjacent Angles is applied. Not in this situation

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irga5000 [103]

Answer:

59°

Step-by-step explanation:

Difference=54-(-5)

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