The equation of the line which has a gradient of 2 and passes through the point (1,4) is y = 2x + 2.
We have given that,
A line that has a gradient of 2 and passes through the line (1, 4).
We have to determine the equation of the line,
<h3>What is the gradient?</h3>
The gradient also known as the slope is the defined as
Gradient (m) = change in y coordinate / change in x coordinate
The equation of a line passing through a given point is given by the following equation
y – y₁ = m(x – x₁)
How to determine the equation of the line passing through point (1,4)
x coordinate (x₁) = 1
y coordinate (y₁) = 4
Gradient (m) = 2
Equation =
y – y₁ = m(x – x₁)
y – 4 = 2(x – 1)
Clear bracket
y – 4 = 2x – 2
Make y the subject by adding 4 to both sides
y – 4 + 4 = 2x – 2 + 4
y = 2x + 2
The equation of the line which has a gradient of 2 and passes through the point (1,4) is y = 2x + 2.
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Answer:
Step-by-step explanation:
hope this helps :)
Answer:
d y=4x + 5
Step-by-step explanation:
Is parallel beacause they have the same slope, remember
y=ax + c
where a is the slope of the line
They belong to the number group of INTEGERS
Answer:
For 
, x = 2, or x = - 2.
Step-by-step explanation:
Here, the given expression is :
Now, using the ALGEBRAIC IDENTITY:
Comparing this with the above expression, we get
⇒Either (x-2) = 0 , or ( x + 2) = 0
So, if ( x- 2) = 0 ⇒ x = 2
and if ( x + 2) = 0 ⇒ x = -2
Hence, for , x = 2, or x = - 2.
