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PilotLPTM [1.2K]

3 years ago

8

Which is a qualitative variable? A) flavors of coffee B) prices of coffee ounces of coffee beans per bag D) percentage of caffei

ne in coffee

2 answers:

Rama09 [41]3 years ago

5 0

I think its me before you did that you need ti wirte it

Pavlova-9 [17]3 years ago

4 0

Answer: A

Step-by-step explanation:

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A rancher has 4 comma 700 feet of fencing available to enclose a rectangular area bordering a river. he wants to separate his co

guapka [62]

Area=length*width
let the sides perpendicular to the river be x
then the side parallel to the river is 4,700-2x
A(x)=x(4700-2x)
A(x)=4700x-2x^2

This a quadratic function with a=-2 and b=4700
thus
Maximum area occurs where x=-b/2a=-4700(-2*2)=1,175 ft
length=4700-2(1175)=2,350 ft

4 0

3 years ago

Isabel bought a new jacket for $48 before tax. She paid 6.5% in sales tax. How much was the sales tax?

AleksandrR [38]

C) $3.12
$48*.065=$3.12

6 0

3 years ago

The table below shows all of the possible outcomes for rolling two six-sided number cubes. A table with 36 possible outcomes. Th

barxatty [35]

The image is missing, we have attached the image.

Answer:

The of getting an even number in first and an odd number second is $\frac{1}{4}\ or\ 0.25$ .

Step-by-step explanation:

Given,

Total number of outcomes = 36

We have to find the probability of rolling an even number first and an odd number second.

Solution,

Firstly we will find out the possible outcomes;

$(2,1),\ (2,3),\ (2,5),\ (4,1),\ (4,3),\ (4,5),\ (6,1),\ (6,3),\ (6,5),$

So the total number of outcomes = 9

Now according to the formula of probability, which is;

$P(E)=\frac{\textrm{total number of possible outcomes}}{\textrm{total number of outcomes}}$

Now on putting the values, we get;

P(of getting an even number in first and an odd number second)= $\frac{9}{36}=\frac{1}{4}=0.25$

Hence The of getting an even number in first and an odd number second is $\frac{1}{4}\ or\ 0.25$ .

5 0

3 years ago

Read 2 more answers

Assuming boys and girls are equally likely, find the probability of a couple having a baby boy when their fifth child is born,

GREYUIT [131]

Answer: $\dfrac{1}{2}$

Step-by-step explanation:

If we assume that the boys and girls are equally likely, so the probability of having a girl is equal to probability of having a boy = $\dfrac{1}{2}$ .

Let B = Event of having a boy.

G= Event of having a girl.

Since both events are independent of each other . (Events that do not depends on each other.)

So irrespective of the four baby boy , the probability that the fifth child is a boy = $\dfrac{1}{2}$

Therefore , the probability of a couple having a baby boy when their fifth child is born, given that the first four children were all boys= $\dfrac{1}{2}$

8 0

3 years ago

What is the rate of change (8,13), (-13,-15)

3241004551 [841]

Answer:

28/21

Step-by-step explanation:

You would do y1 - y2 for the numerator which gets you 28. Then you would do x1 - x2 for the denominator which gets you 21. The rate of change is also the slope.

Hope this helps!

5 0

3 years ago