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7 months ago

9/2h = -1 what does h equal too?

Mathematics

2 answers:

iren [92.7K]7 months ago

6 0

9/2h=-1 so 9=-2h with becomes this (9/-2)=h

Sergeeva-Olga [200]7 months ago

5 0

$\textbf {The answer is h = -2/9.}$

$\textrm {We are given that 9/2h = -1. Hence, divide by 9/2 on both sides.}$

$\frac{9/2h}{9/2} = \frac{-1}{9/2}$

$\boxed {h = -\frac{2}{9}}$

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Complete each statement from the information given and state the reasons and the triangle criterion you used.

TiliK225 [7]

Answer:

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Step-by-step explanation:

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5 0

2 years ago

Help!! 50 points and brainliest!

Viktor [21]

Answer:

Second choice:

$x=2t$

$y=4t^2+4t-3$

Fifth choice:

$x=t+1$

$y=t^2+4t$

Step-by-step explanation:

Let's look at choice 1.

$x=t+1$

$y=t^2+2t$

I'm going to subtract 1 on both sides for the first equation giving me $x-1=t$ . I will replace the $t$ in the second equation with this substitution from equation 1.

$y=(x-1)^2+2(x-1)$

Expand using the distributive property and the identity $(u+v)^2=u^2+2uv+v^2$ :

$y=(x^2-2x+1)+(2x-2)$

$y=x^2+(-2x+2x)+(1-2)$

$y=x^2+0+-1$

$y=x^2$

So this not the desired result.

Let's look at choice 2.

$x=2t$

$y=4t^2+4t-3$

Solve the first equation for $t$ by dividing both sides by 2:

$t=\frac{x}{2}$ .

Let's plug this into equation 2:

$y=4(\frac{x}{2})^2+4(\frac{x}{2})-3$

$y=4(\frac{x^2}{4})+2x-3$

$y=x^2+2x-3$

This is the desired result.

Choice 3:

$x=t-3$

$y=t^2+2t$

Solve the first equation for $t$ by adding 3 on both sides:

$x+3=t$ .

Plug into second equation:

$y=(x+3)^2+2(x+3)$

Expanding using the distributive property and the earlier identity mentioned to expand the binomial square:

$y=(x^2+6x+9)+(2x+6)$

$y=(x^2)+(6x+2x)+(9+6)$

$y=x^2+8x+15$

Not the desired result.

Choice 4:

$x=t^2$

$y=2t-3$

I'm going to solve the bottom equation for $t$ since I don't want to deal with square roots.

Add 3 on both sides:

$y+3=2t$

Divide both sides by 2:

$\frac{y+3}{2}=t$

Plug into equation 1:

$x=(\frac{y+3}{2})^2$

This is not the desired result because the $y$ variable will be squared now instead of the $x$ variable.

Choice 5:

$x=t+1$

$y=t^2+4t$

Solve the first equation for $t$ by subtracting 1 on both sides:

$x-1=t$ .

Plug into equation 2:

$y=(x-1)^2+4(x-1)$

Distribute and use the binomial square identity used earlier:

$y=(x^2-2x+1)+(4x-4)$

$y=(x^2)+(-2x+4x)+(1-4)$

$y=x^2+2x+-3$

$y=x^2+2x-3$ .

This is the desired result.

3 0

2 years ago

Read 2 more answers

The range of the following relation R {(3, −2), (1, 2), (−1, −4), (−1, 2)}

Oxana [17]

I think the rang numbers are -2 , 2 , -4 , and 2. i hope that correct.

8 0

2 years ago

HELP I NEED HELP ASAP

olga55 [171]

B

I’m not that sure tbh

8 0

2 years ago

Read 2 more answers

The mean of the heights of three buildings A,B and C is 14.2m. The mean of the heights of five buildings A,B,C, D and E is 14.8m

Jobisdone [24]

<h3>Answer: 15.7 meters</h3>

========================================================

Work Shown:

s = sum of the heights of buildings A,B,C

s/3 = mean of the heights of buildings A,B,C

s/3 = 14.2

s = 3*14.2

s = 42.6

The buildings A,B,C have their heights add up to 42.6

--------------

r = sum of the heights of buildings A,B,C,D,E

r/5 = mean of the heights of buildings A,B,C,D,E

r/5 = 14.8

r = 5*14.8

r = 74

--------------

r-s = (sum of heights of A,B,C,D,E)-(sum of heights of A,B,C)

r-s = sum of the heights of buildings D and E

r-s = 74-42.6

r-s = 31.4

(r-s)/2 = mean height of buildings D and E

(r-s)/2 = 31.4/2

(r-s)/2 = 15.7 meters is the average height of buildings D and E.

4 0

1 year ago