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ser-zykov [4K]
3 years ago
7

What’s the vertex y=-1/2(x+3)^2-1

Mathematics
2 answers:
Gemiola [76]3 years ago
8 0
Use the vertex form,
y
=
a
(
x
−
h
)
2
+
k
y
=
a
(
x
-
h
)
2
+
k
, to determine the values of
a
a
,
h
h
, and
k
k
.
a
=
−
1
2
a
=
-
1
2
h
=
−
3
h
=
-
3
k
=
−
1
k
=
-
1
Find the vertex
(
h
,
k
)
(
h
,
k
)
.
(
−
3
,
−
1
)
Lena [83]3 years ago
7 0

Answer:

vertex = (- 3, - 1 )

Step-by-step explanation:

The equation of a parabola in vertex form is

y = a(x - h)² + k

where (h, k) are the coordinates of the vertex and a is a multiplier

y = - \frac{1}{2} (x + 3)² - 1 ← is in vertex form

with vertex = (- 3, - 1 )

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What two numbers have a product of -2 and a sum of 7
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<em>Greetings from Brasil...</em>

According to the statement of the question, we can assemble the following system of equation:

X · Y = - 2      i

X + Y = 7       ii

isolating X from i and replacing in ii:

X · Y = - 2

X = - 2/Y

X + Y = 7

(- 2/Y) + Y = 7     <em>multiplying everything by Y</em>

(- 2Y/Y) + Y·Y = 7·Y

- 2 + Y² = 7X     <em> rearranging everything</em>

Y² - 7X - 2 = 0      <em>2nd degree equation</em>

Δ = b² - 4·a·c

Δ = (- 7)² - 4·1·(- 2)

Δ = 49 + 8

Δ = 57

X = (- b ± √Δ)/2a

X' = (- (- 7) ± √57)/2·1

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X' = (7 - √57)/2

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