All categories

3 years ago

At a restaurant, 36%

Mathematics

1 answer:

Gekata [30.6K]3 years ago

3 0

Answer:

128

Step-by-step explanation:

72 people are vegetarians so 200-72=128

You might be interested in

If the line passing through the points (a, 1) and (−2, 6) is parallel to the line passing through the points (−12, 9) and (a + 2

iren2701 [21]

$\frac{6 - 1}{ - 2 - a} = \frac{9 - 1}{ - 12 - a - 2} \\ \frac{5}{ - 2 - a} = \frac{8}{ - 14 - a} \\ 16 + 8a = 70 + 5a \\ 3a = 54 > > a = 18$

8 0

3 years ago

Put it in order yes or no?and how do yk if it is or not

Serggg [28]

9514 1404 393

Answer:

yes, yes, no, no

Step-by-step explanation:

An equation is linear if no term has a variable with an exponent other than 0 or 1. There can be no products of variables.

The equations with terms x³ or x² will not be linear.

(a, b) linear (yes)

(c, d) not linear (no)

6 0

3 years ago

Read 2 more answers

Dont really understand how to do this

bija089 [108]

Answers:

$t_{10} = -22 \ \text{ and } S_{10} = -85$

========================================================

Explanation:

$t_1 = \text{first term} = 5\\t_2 = \text{first term}-3 = t_1 - 3 = 5-3 = 2$

Note we subtract 3 off the previous term (t1) to get the next term (t2). Each new successive term is found this way

$t_3 = t_2 - 3 = 2-3 = -1\\t_4 = t_3 - 3 = -1-3 = -4$

and so on. This process may take a while to reach $t_{10}$

There's a shortcut. The nth term of any arithmetic sequence is

$t_n = t_1+d(n-1)$

We plug in $t_1 = 5 \text{ and } d = -3$ and simplify

$t_n = t_1+d(n-1)\\t_n = 5+(-3)(n-1)\\t_n = 5-3n+3\\t_n = -3n+8$

Then we can plug in various positive whole numbers for n to find the corresponding $t_n$ value. For example, plug in n = 2

$t_n = -3n+8\\t_2 = -3*2+8\\t_2 = -6+8\\t_2 = 2$

which matches with the second term we found earlier. And,

$tn = -3n+8\\t_{10} = -3*10+8\\t_{10} = -30+8\\t_{10} = \boldsymbol{-22} \ \textbf{ is the tenth term}$

---------------------

The notation $S_{10}$ refers to the sum of the first ten terms $t_1, t_2, \ldots, t_9, t_{10}$

We could use either the long way or the shortcut above to find all $t_1$ through $t_{10}$ . Then add those values up. Or we can take this shortcut below.

$Sn = \text{sum of the first n terms of an arithmetic sequence}\\S_n = (n/2)*(t_1+t_n)\\S_{10} = (10/2)*(t_1+t_{10})\\S_{10} = (10/2)*(5-22)\\S_{10} = 5*(-17)\\\boldsymbol{S_{10} = -85}$

The sum of the first ten terms is -85

-----------------------

As a check for $S_{10}$ , here are the first ten terms:

t1 = 5
t2 = 2
t3 = -1
t4 = -4
t5 = -7
t6 = -10
t7 = -13
t8 = -16
t9 = -19
t10 = -22

Then adding said terms gets us...

5 + 2 + (-1) + (-4) + (-7) + (-10) + (-13) + (-16) + (-19) + (-22) = -85

This confirms that $S_{10} = -85$ is correct.

6 0

2 years ago

PLEEAASEE HELP!!! Suppose Q and R are independent events. Find P(Q and R) if P(Q) = 4/5 and P(R) = 4/11.

kari74 [83]

The answer is C. 16/55 because P(Q and R) = P (Q) . P (R) (for independent events Q and R)

So, the prob. is 4/5 * 4/11 = 16/55 = D.

5 0

3 years ago

Read 2 more answers

A rectangular piece of cardboard is 16y cm long and 23 cm wide. Four square pieces of cardboard whose sides are 6y cm each are c

Anna11 [10]

Answer:

Area of remaining cardboard is 224y^2 cm^2

a + b = 226

Step-by-step explanation:

The complete and correct question is;

A rectangular piece of cardboard is 16y cm long and 23y cm wide. Four square pieces of cardboard whose sides are 6y cm each are cut away from the corners. Find the area of the remaining cardboard. Express your answer in terms of y. If your answer is ay^b, then what is a+b?

Solution;

Mathematically, at any point in time

Area of the cardboard is length * width

Here, area of the total cardboard is 16y * 23y = 368y^2 cm^2

Area of the cuts;

= 4 * (6y)^2 = 4 * 36y^2 = 144y^2

The area of the remaining cardboard will be :

368y^2-144y^2

= 224y^2

Compare this with;

ay^b

a = 224, and b = 2

a + b = 224 + 2 = 226

3 0

3 years ago