That the equation could be combined into like terms
That's not a linear system, but you have an awesome school system for giving you this problem.
Multiply by 6xy to clear the fractions.
That's a second degree equation, also known as a conic. That one happens to be a hyperbola.
Let's clear the fractions from the second equation, multiplying out common denominator xy:
We are being asked to find the meet of two hyperbolas, so we expect two answers, a quadratic equation.
Substituting,
We have to rule out x=0 because it's in the denominator.
Answer: (44/19, 33/20)
The number of squares on a chess or checker board is 64 and to find the square root of 64 which is 8*8=64 so the answer is 8
Answer:
EF = 20 cm
Step-by-step explanation:
Here, we want to find the length of EF
To do this, we use the principle of similar triangles
The similar triangles we are considering here will be ;
FEA and FBD
when two triangles are similar, the ratio of their corresponding sides are equal
Let us calculate DC first
we can use Pythagoras’ theorem here and it is that the square of the hypotenuse equals the sum of the square of the two other sides
Using the triangle EDC
15^2 = 12^2 + DC^2
DC^2 = 225-144
DC^2 = 81
DC = 9
So the entire length of BD is 9 + 12 = 21 cm
Thus, we have it that;
Let EF be x
so DF = 15 + x
Hence;
BD/DF = AE/EF
21/15+x = 12/x
21x = 12(15 + x)
21x = 180 + 12x
21x-12x = 180
9x = 180
x = 180/9
x = 20 cm
EF = 20 cm
