Just need a step-by-step on how to do it

Triangle ABC has vertices A(-2, 3), B(0, 3), and C(-1,-1). Find the coordinates of the image after a reflection over the

motikmotik

Given:

Given that the triangle ABC has vertices A(-2,3), B(0,3) and C(-1,-1).

We need to determine the coordinates of the image after a reflection over the x - axis.

Let A'B'C' denote the coordinates of the triangle after a reflection over the x - axis.

Coordinates of the point A':

The general rule to reflect the coordinate across the x - axis is given by

$(x,y)\rightarrow (x,-y)$

Substituting the point A(-2,3), we get;

$(-2,3)\rightarrow (-2,-3)$

Thus, the coordinates of the point A' is (-2,-3)

Coordinates of the point B':

The general rule to reflect the coordinate across the x - axis is given by

$(x,y)\rightarrow (x,-y)$

Substituting the point B(0,3), we get;

$(0,3)\rightarrow (0,-3)$

Thus, the coordinates of the point B' is (0,-3)

Coordinates of the point C':

The general rule to reflect the coordinate across the x - axis is given by

$(x,y)\rightarrow (x,-y)$

Substituting the point C(-1,-1), we get;

$(-1,-1)\rightarrow (-1,1)$

Thus, the coordinates of the point C' is (-1,1)

Hence, the coordinates of the image after a reflection over the x - axis is A'(-2,-3), B(0,-3) and C(-1,1)

8 0

3 years ago

689x+47x-89 dose anyone know how to solve this?

Korvikt [17]

Answer:

736x-89

Step-by-step explanation:

i think all you can do here is add the numbers that have an X in them so adding 689x+47x=736x and you leave the 89 so it becomes 736x-89

4 0

1 year ago

Read 2 more answers

Please help I’m timed

kupik [55]

It’s the second one :)

3 0

2 years ago

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A spinner is divided into many different color sectors. Some sectors are larger than others. The spinner was spun 300 times. The

Furkat [3]

Solutions

We know that a spinner was divided into many different color sectors. Some sectors are larger than others. The spinner was spun 300 times. The results were tallied up and were written in a table.

Red:93

Blue:59

Green:105

Yellow:43

The spinner landed the highest on green. To find the probability that the next spin will land on green we have add all the numbers and simplify them.

93 + 59 + 105 + 43 = 300

Out of 300 the spinner landed to green 105 times. We have the fraction 105/300.

105/300 can be reduced. To reduce the fraction we need to the GCF of 105 and 300. The GCF is 15.

We can reduce the fraction by dividing the numerator and denominator by the GCF = 15.

105 ÷ 15 = 7

300 ÷ 15 = 20

Our new fraction is 7/20

The probability that the next spin will land on green is 7/20.
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To get the answer to part (B) we have to add the results of red and green then simplify.

93 + 105 = 198

The fraction is 198/300. 198/300 can be reduced. To reduce the fraction we need to the GCF of 105 and 300. The GCF is 6.

We can reduce the fraction by dividing the numerator and denominator by the GCF = 6.

198 ÷ 6 = 33

300 ÷ 6 = 50

The new fraction is 33/50

The probability that the next spin will land on either green or red is 33/50.

Hope this helps

4 0

2 years ago

#6 from the paper please

BabaBlast [244]

Answer:

EK = 9

Step-by-step explanation:

x + 11 = -5 + 2x -5 + 2x

x+11 = -10 + 4x

11 = 3x - 10

3x = 21

x = 7

EK =-5 + 2 × 7

EK = 14 - 5

EK = 9

6 0

2 years ago

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