Help please this is due by 10:35.

Mathematics

2 answers:

USPshnik [31]4 years ago

7 0

Answer:

Im pretty sure its A,B, and D

Step-by-step explanation:

loris [4]4 years ago

4 0

It's a reflection across the y axis because They are both still equal(all sides are equal) but flipped around. Also, if you calculate, all the midpoints of corresponding points are on the y axis, which shows that it is a reflection over the y axis and nothing more.

It could also be reflect across the x axis, then the y axis, then the x axis again because the reflections across the x axis cancel out with each other. So it is basically is a reflection across the y axis.

Choice 4 because when you rotate it by 180 it lands in the third quadrant exactly one reflection away. When you reflect it across the x axis, it becomes the desired triangle.

Choices 1 and 2 and 4.

You might be interested in

Which one is greater 3/10 or 2/5

Andreyy89

Answer:

2/5

Step-by-step explanation:

2/5=4/10

4 0

3 years ago

Read 2 more answers

PLEASE HELP WILL MARK BRAINLIST !!!!!!!!

kondaur [170]

Answer:

in my knowledge

Option A..

Step-by-step explanation:

This is an arithmetic sequence since there is a common difference between each term. ... This is the formula of an arithmetic sequence.

8 0

3 years ago

We are given a sequence of five non-zero numbers, where the sum of each term and its neighboring terms is 15 or 25. Find the sum

PSYCHO15rus [73]

We have a sequence that meets the given criteria, and with that information, we want to get the sum of all the terms in the sequence.

We will see that the sum tends to infinity.

So we have 5 terms;

A, B, C, D, E.

We know that the sum of each term and its neighboring terms is 15 or 25.

then:

A + B + C = 15 or 25
B + C + D = 15 or 25
C + D + E = 15 or 25

Now, we want to find the sum of all the terms in the sequence (not only the 5 given).

Then let's assume we write the sum of infinite terms as:

$a_1 + a_2 + a_3 + a_4 + a_5 + a_6 + ...$

Now we group that sum in pairs of 3 consecutive terms, so we get:

$(a_1 + a_2 + a_3) + (a_4 + a_5 + a_6) + ...$

So we will have a sum of infinite of these, and each one of these is equal to 15 or 25 (both positive numbers). So when we sum that infinite times (even if we always have the smaller number, 15) the sum will tend to be infinite.

Then we have:

$(a_1 + a_2 + a_3) + (a_4 + a_5 + a_6) + ... \to \infty$