Answer:
D. 7.25
Step-by-step explanation:
9.50-2.25=x
9.50-2.25= 7.25
Answer:
B. Subtract
Step-by-step explanation:
Just like when multiplying exponents, you're really just adding them together. This is the same case, when you're "dividing" the exponents, you're really just subtracting them.
Answer:

Step-by-step explanation:
<h2><em><u>Given</u></em><em><u> </u></em><em><u>Question</u></em><em><u>, </u></em></h2>
To find the value of x.
<h2><em><u>Solution</u></em><em><u>:</u></em></h2>
<em><u>According</u></em><em><u> </u></em><em><u>to</u></em><em><u> </u></em><em><u>Pythagoras</u></em><em><u> </u></em><em><u>Theorem</u></em><em><u>-</u></em>






<h2><em><u>Result</u></em><em><u>:</u></em></h2>
<em><u>Hence</u></em><em><u>,</u></em><em><u> </u></em><em><u>the</u></em><em><u> </u></em><em><u>required</u></em><em><u> </u></em><em><u>value</u></em><em><u> </u></em><em><u>of</u></em><em><u> </u></em><em><u>x</u></em><em><u> </u></em><em><u>is</u></em><em><u> </u></em>
<em><u>
</u></em>
the final speed in m/s of the 10.0 kg is 2.53 m/s .
<u>Step-by-step explanation:</u>
Here we have , A 10.0 kg and a 2.0 kg cart approach each other on a horizontal friction less air track. Their total kinetic energy before collision is 96 ). Assume their collision is elastic. We need to find What is the final speed in m/s of the 10.0 kg mass if that of the 2.0 kg mass is 8.0 m/s . Let's find out:
We know that in an elastic collision :
⇒ Total kinetic energy before collision = Total kinetic energy after collision
⇒ 
⇒ 
⇒ 
⇒ 
⇒ 
⇒ 
Therefore , the final speed in m/s of the 10.0 kg is 2.53 m/s .