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Archy [21]
3 years ago
6

Jackson wants to divide a 3/4 pound box of trial mix into small bags.Each of the bags will hold 1/12 pound of trail mix.How many

bags of trail mix can jackson fill?
Mathematics
1 answer:
maksim [4K]3 years ago
3 0
3/48 because I said so and I’m smart jk
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3(-4y+5)-8(-2y-4) can be written in the form (ay+b) by following the following steps:
Dominik [7]

Answer:

Does the correct answer necessarily HAVE to be one of those three options? Because I'm looking at the steps and there seems to no mistakes at all. Forgive me if I'm mistaken though!

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
Write each expression as an algebraic​ (nontrigonometric) expression in​ u, u > 0.
max2010maxim [7]

Answer:

\displaystyle \sin\left(2\sec^{-1}\left(\frac{u}{10}\right)\right)=\frac{20\sqrt{u^2-100}}{u^2}\text{ where } u>0

Step-by-step explanation:

We want to write the trignometric expression:

\displaystyle \sin\left(2\sec^{-1}\left(\frac{u}{10}\right)\right)\text{ where } u>0

As an algebraic equation.

First, we can focus on the inner expression. Let θ equal the expression:

\displaystyle \theta=\sec^{-1}\left(\frac{u}{10}\right)

Take the secant of both sides:

\displaystyle \sec(\theta)=\frac{u}{10}

Since secant is the ratio of the hypotenuse side to the adjacent side, this means that the opposite side is:

\displaystyle o=\sqrt{u^2-10^2}=\sqrt{u^2-100}

By substitutition:

\displaystyle= \sin(2\theta)

Using an double-angle identity:

=2\sin(\theta)\cos(\theta)

We know that the opposite side is √(u² -100), the adjacent side is 10, and the hypotenuse is u. Therefore:

\displaystyle =2\left(\frac{\sqrt{u^2-100}}{u}\right)\left(\frac{10}{u}\right)

Simplify. Therefore:

\displaystyle \sin\left(2\sec^{-1}\left(\frac{u}{10}\right)\right)=\frac{20\sqrt{u^2-100}}{u^2}\text{ where } u>0

4 0
3 years ago
How do you understand what happens on a fraction number line and how do you know where the fraction is. Tell me how we will be a
frozen [14]

9514 1404 393

Answer:

  understand what the fraction means

Step-by-step explanation:

First of all, you need to <em>understand what 2/3 means</em>. It means 1 whole has been divided into 3 equal parts, and you're concerned with 2 of those parts.

In the number line in the first attachment, the space between 0 and 1 has been divided into 3 equal parts. The decimal value (rounded) is shown at each tick mark. The point marked "2/3" is located at the second of those divisions, counting from zero.

__

The same fraction is located on the same number line in the second attachment. That number line is marked with divisions at intervals of 1/10, so there are 10 of them between 0 and 1. The value 2/3 is represented by the point that is (2/3)(10) = 6 2/3 of those intervals, so is between 0.6 and 0.7 on the number line.

__

If the number line were divided into 12ths, then the fraction 2/3 would be located at the 8th tick mark, counting from 0. (2/3)(12) = 8 That is shown in the third attachment.

5 0
3 years ago
Can someone help I cant understand a method for this pls ASAP
kvv77 [185]

Answer:

105 hours

Step-by-step explanation:

→ Find how many days in a week

7

→ Multiply this by his gaming time

7 × 15 = 105

3 0
2 years ago
Read 2 more answers
The sum of squares of two consecutive odd numbers is 514 find the numbers ​
amid [387]

Correct Question : The sum of squares of two consecutive positive odd numbers is 514. Find the numbers.

\rule{130}1

Solution :

Let the two consecutive positive odd numbers be x and (x + 2)

\rule{130}1

☯ \underline{\boldsymbol{According\: to \:the\: Question\:now :}}

:\implies\sf x^2 + (x + 2)^{2} = 514 \\\\\\:\implies\sf x^2 + x^2 + 4x + 4 = 514\\\\\\:\implies\sf 2x^2 + 4x + 4 = 514 \\\\\\:\implies\sf 2x^2 + 4x = 514 - 4\\\\\\:\implies\sf 2x^2 + 4x = 510 \\\\\\:\implies\sf 2x^2 + 4x - 510 = 0\\\\\\:\implies\sf x^2 + 2x - 255 = 0 \:\:\:\:\:\Bigg\lgroup \bf{Dividing\:by\:2}\Bigg\rgroup\\\\\\:\implies\sf x^2 + 17x - 15x - 255 = 0\\\\\\:\implies\sf x(x + 17) - 15(x + 17) = 0\\\\\\:\implies\sf (x + 17) (x - 15)\\\\\\:\implies\sf x = - 17\:or\:x = 15\\\\\\:\implies\underline{\boxed {\sf x = 15}}\:\:\:\:\:\Bigg\lgroup \bf{Positive\:odd\: number}\Bigg\rgroup

When,

\bullet\: \textsf {x = } \textbf {15}

\bullet\: \sf x + 2 = 15 + 2 =\textbf{ 17}

\therefore\:\underline{\textsf{The required positive integer is \textbf{15 and 17}}}.

5 0
3 years ago
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