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guapka [62]
1 year ago
12

Annilee's present age is two-thirds of Jessie's present age. In 14 years the sum of their ages will be 103 years. Find their pre

sent ages.
Mathematics
1 answer:
Butoxors [25]1 year ago
7 0

The present age of Annillee, which is two-thirds of Jessie's present age, is <u>30 years</u>, while Jessie's is <u>45 years</u>.

<h3>How are the ages determined?</h3>

Their present ages can be determined using a system of equations as below.

<h3>Data and Calculations:</h3>

Let the present age of Annilee = ²/₃y

Let the present of Jessie = y

Ages of Annilee and Jessie in 14 years:

Annilee's age = ²/₃y + 14

Jessie's age = y + 14

Sum of their ages in 14 years = ²/₃y + 14 + y + 14

= 103

²/₃y + 14 + y + 14 = 103

²/₃y + y = 75

1²/₃y = 75

y = 75/1²/₃

y = 75/5 x 3

y = 45

<h3>Present Ages:</h3>

Annilee = ²/₃y = ²/₃ x 45 = 30 years

Jessie = y = 45

<u>Check</u>:

²/₃ x 45 + 14 = 44

45 + 14 = 59

Sum of ages in 14 years = 103 (59 + 44) or (30 + 14 + 45 + 14)

Thus, at present, Annilee's age is <u>30 years</u>, while Jessie is <u>45 years</u>.

Learn more about equations at brainly.com/question/2972832

#SPJ1

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kow [346]

Answer:

<h2>Here's what makes an integer odd:</h2>
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<h2>Here's what makes an integer even:</h2>
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  • So, if x was an odd number, adding it by 2, 4, 6, etc. will result in another odd number.

Here's an example:

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<em>See how x is an odd number and the sum of the number and two makes another odd number? </em>

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Answer:

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