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Rom4ik [11]
1 year ago
7

Given that cos(theta) = -2 radical 5/5, and is in Quadrant II, what is cos(2theta)?

Mathematics
1 answer:
gtnhenbr [62]1 year ago
5 0

cos \theta =  \frac{ - 2 \sqrt{5} }{5}

cos 2\theta = 2cos {}^{2}  \theta - 1 \\ cos2 \theta = 2( \frac{ - 2 \sqrt{5} }{5} ) {}^{2}  - 1 \\ cos2 \theta = 2( \frac{20}{ \\ 25} ) - 1 \\ cos2 \theta =  \frac{40 - 25}{25}  =  \frac{15}{25}  =  \frac{3}{5}

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