Samantha is studying the population growth of an endangered birth. The growth can be modeled by the equation B(t) 100 + 3/5t^5 ,

Question

1 year ago

10

Samantha is studying the population growth of an endangered birth. The growth can be modeled by the equation B(t) 100 + 3/5t^5 ,

where B is the population after t, time in years.Samantha is studying the population growth of an endangered birth. The growth can be modeled by the equation B(t) 100 + 3/5t^5 , where B is the population after t, time in years.

Mathematics

1 answer:

solong [7] · Answer 1 · 2024-03-22T02:55:21+03:00

The value of the population of the growth of an endangered birth after 5 years is 1975

<h3>How to determine the population after 5 years?</h3>

The population function is given as:

B(t) = 100 + 3/5t^5

At 5 years, the value of t is 5

So, we have

t = 5

Next, we substitute 5 for t in the equation B(t) = 100 + 3/5t^5

This gives

B(5) = 100 + 3/5 * 5^5

Evaluate the exponent

B(5) = 100 + 3/5 * 3125

Evaluate the product

B(5) = 100 + 1875

Evaluate the sum

B(5) = 1975

Hence, the value of the population of the growth of an endangered birth after 5 years is 1975

Read more about exponential functions at:

brainly.com/question/2456547

#SPJ1