Answer:
Solution given:
letA=(10,-4)
B=(-2,-4)
centre[C](h,k)=
radius=units
we have
Equation of a circle is;
(x-h)²+(y-k)²=r²
(x-4)²+(y+4)²=36
or.
x²-8x+16+y²+8y+16=36
x²-8x+8y+y²=36-32
x²-8x+8y+y²=4
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Answer: Option C.
Step-by-step explanation:
The equation of the line in slope-intercept form is:
Where the slope is "m" and the intersection of the line with the y-axis is "b".
Given the function f(x) in the form , you can identify that:
This means that the line passes through the origin (0,0)
And from the function g(x) in the form , , you can identify that:
This means that the line of the function g(x) and the line of the function f(x) have the same slope, but the line of g(x) passes through the point (0,-16)
Therefore, the graph of f(x) must be shifted 16 units down to produce the graph of g(x)
Answer:
a = 16*3.1415/3 = 16.76
Step-by-step explanation:
a =pi*r^2
r =D/2
r = 8/2
r = 4
a = pi*4^2
a=pi16
pi = 3.1416
Think of numbers that when they are divided by 10, the remainder is 9.
So numbers like: 19, 29, 39, 49, 59, 69, 79, 89, and 99.
Now numbers that when they are divided by 9, the remainder is 8.
So numbers like: 17, 26, 35, 44, 53, 62, 71, 80, 89, and 98.
Now the number that is alike from the two sets of numbers is n.
n=89
Double check your work.
Divide 89 by 10. Remainder of 9
Divide 89 by 9. Remainder of 8.
Hope this helps :)
Factor-
1. Factor 3x2 + 6x if possible.
Look for monomial (single-term) factors first; 3 is a factor of both 3x2
and 6x and so is x . Factor them out to get
3x2 + 6x = 3(x2 + 2x1 = 3x(x+ 2) .
2. Factor x2 + x - 6 if possible.
Here we have no common monomial factors. To get the x2 term
we'll have the form (x +-)(x +-) . Since
(x+A)(x+B) = x2 + (A+B)x + AB ,
we need two numbers A and B whose sum is 1 and whose product is
-6 . Integer possibilities that will give a product of -6 are
-6 and 1, 6 and -1, -3 and 2, 3 and -2.
The only pair whose sum is 1 is (3 and -2) , so the factorization is
x2 + x - 6 = (x+3)(x-2) .
3. Factor 4x2 - 3x - 10 if possible.
Because of the 4x2 term the factored form wli be either
(4x+A)(x +B) or (2x+A)(2x+B) . Because of the -10 the integer possibilities
for the pair A, B are
10 and -1 , -10 and 1 , 5 and -2 . -5 and 2 , plus each of
these in reversed order.
Check the various possibilities by trial and error. It may help to write
out the expansions
(4x + A)(x+ B) = 4x2 + (4B+A)x + A8
1 trying to get -3 here
(2x+A)(2x+B) = 4x2 + (2B+ 2A)x + AB
Trial and error gives the factorization 4x2 - 3x - 10 - (4x+5)(x- 2) .
4. Difference of two squares. Since (A + B)(A - B) = - B~ , any
expression of the form A' - B' can be factored. Note that A and B
might be anything at all.
Examples: 9x2 - 16 = (3x1' - 4' = (3x +4)(3x - 4)
x2 - 29 = x2 - (my)* = (x+ JTy)(x- my)
For any of the above examples one could also use the