When we have this equation:
CO(g) + Cl2(g) ↔ COCl2(g)
intial 0.147 0.175 0
change -X -X +X
final (0.147-X) (0.175-X) X
so from the ICE table, we substitute in Kc formula :(when we have Kc = 255)
Kc = [COCl2]/[CO][Cl2]
255= X / (0.147-X)(0.175-X)
255 = X / (X^2 - 0.322 X + 0.025725)
X = 0.13
∴[CO] = 0.147 - X = 0.147 - 0.13
= 0.017 m
Answer:
Kindly check the explanation section.
Explanation:
From the description given in the question above, that is '' H subscript f to the power of degree of the reaction" we have that the description matches what is known as the heat of formation of the reaction, ∆fH° where the 'f' is a subscript.
In order to determine the heat of formation of any of the species in the reaction, the heat of formation of the other species must be known and the value for the heat of reaction, ∆H(rxn) must also be known. Thus, heat of formation can be calculated by using the formula below;
∆H(rxn) = ∆fH°( products) - ∆fH°(reactants).
That is the heat of formation of products minus the heat of formation of the reaction g specie(s).
Say heat of formation for the species is known as N(g) = 472.435kj/mol, O(g) = 0kj/mol and NO = unknown, ∆H°(rxn) = −382.185 kj/mol.
−382.185 = x - 472.435kj/mol = 90.25 kJ/mol
Chemical? Perhaps because it is changing?
E is the correct answer because both endothermic and exothermic reactions require activation energy. the reactants have less potential energy than do the products. Energy must be input in order to raise the particles up to the higher energy level.
Use the specific heat equation for each one:
Q = mCT
m is mass
T is change in temp
C is spec heat
You will not only have to calculate three different specific heats, but also do the heat of vaporization and heat of fusion.
Heat of vaporization is 3.33 * 10^5 J/Kg
Heat of Fusion is 2.26 * 10^6 J/Kg
You’ll want to make sure all your units match. So change all Kg to g (or g to Kg)
-20 to 0 = mC(Ice)T
Melt ice (fusion) = m(heat of fusion)
0 to 100 = mC(Water)T
Boil (Vaporization) = m(heat of vaporization)
100 to 250 = mC(Steam)T
Then add each one together
