The over all order of the reaction with the rate law of rate=k[A][B] is 2 since the exponent for [A] is 1 and the exponent for [B] is 1 and 1+1=2.
for example the order for the rate law rate=[A]²[B] is 3 since 2+1=3 and the order for a rate law of rate=[A]²[B]³ the order would be 5 since 2+3=5.
I hope this helps. Let me know if anything is unclear.
Answer: The molarity of the malonic acid solution is 0.08335 M
Explanation:
![H_2C_3H_2O_4 +2NaOH\rightarrow Na_2C_3H_2O_4+2H_2O](https://tex.z-dn.net/?f=H_2C_3H_2O_4%20%2B2NaOH%5Crightarrow%20Na_2C_3H_2O_4%2B2H_2O)
To calculate the molarity of acid, we use the equation given by neutralization reaction:
![n_1M_1V_1=n_2M_2V_2](https://tex.z-dn.net/?f=n_1M_1V_1%3Dn_2M_2V_2)
where,
are the n-factor, molarity and volume of acid which is ![H_2C_3H_2O_4](https://tex.z-dn.net/?f=H_2C_3H_2O_4)
are the n-factor, molarity and volume of base which is NaOH.
We are given:
![n_1=2\\M_1=?\\V_1=12.70mL\\n_2=1\\M_2=0.1000M\\V_2=21.17mL](https://tex.z-dn.net/?f=n_1%3D2%5C%5CM_1%3D%3F%5C%5CV_1%3D12.70mL%5C%5Cn_2%3D1%5C%5CM_2%3D0.1000M%5C%5CV_2%3D21.17mL)
Putting values in above equation, we get:
![2\times M_1\times 12.70=1\times 0.1000\times 21.17\\\\M_1=0.08335M](https://tex.z-dn.net/?f=2%5Ctimes%20M_1%5Ctimes%2012.70%3D1%5Ctimes%200.1000%5Ctimes%2021.17%5C%5C%5C%5CM_1%3D0.08335M)
Thus the molarity of the malonic acid solution is 0.08335 M
Answer is: new concentration is 0,168 mg/mL.
d(solution) = 0,842 g/L.
V(solution) = 0,2 mL = 0,0002 L.
V(water) = 0,8 mL.
V₁(solution) = V(solution) + V(water).
V₁(solution) = 0,8 mL + 0,2 mL = 1 mL.
m(solution) = 0,0002 L · 0,842 g/L · 1000.
m(solution) = 0,168 mg.
d₁(solution) = m(solution) / V₁(solution).
d₁(solution) = 0,168 mg/mL.
Answer:
80 ml
Explanation:
From the question,
Applying Dilution formular
MV = mv................... Equation 1
Where M = Molarity of Kl before dilution, V = Volume of Kl before dilution, m = molarity of Kl after dilution, v = volume of Kl after dilution.
make V the subject of the equation
V = mv/M............. Equation 2
Given: m = 1.00 M, v = 200 ml, M = 2.50 M
Substitute these values into equation 2
V = (1.00×200)/2.50
V = 80 ml