How much heat must be transferred to 3500 g of liquid water to change the

A 76.0-gram piece of metal at 96.0 °C is placed in 120.0 g of water in a calorimeter at 24.5 °C. The final temperature in the ca

anygoal [31]

Answer:

S(metal) = 0.66J/g°C

Explanation:

We can find specific heat of a material, S, using the equation:

q = m*S*ΔT

Where q is change in heat, m is the mass of the substance, S specific heat and ΔT change in temperature.

The heat given by the metal is equal to the heat that water absorbs, that is:

m(Metal)*S(metal)*ΔT(Metal) = m(Water)*S(water)*ΔT(water)

Where:

m(Metal) = 76.0g

S(metal) = ?

ΔT(Metal) = 96.0°C-31.0°C = 65.0°C

m(Water) = 120.0g

S(water) = 4.184J/g°C

ΔT(water) = 31.0°C-24.5°C = 6.5°C

Replacing:

76.0g*S(metal)*65.0°C = 120.0g*4.184J/g°C*6.5°C

S(metal) = 0.66J/g°C

The law of conservation applies because the energy is not been created or destroyed. The energy that the metal gives is absorbed by the water.

3 0

3 years ago

A company is testing drinking water and wants to ensure that ca content is below 155 ppm. What is the maximum amount of Ca that

BabaBlast [244]

Answer:

138 mg

Explanation:

A company is testing drinking water and wants to ensure that Ca content is below 155 ppm (= 155 mg/kg), that is, 155 milligrams of calcium per kilogram of drinking water. We need to find the maximum amount of calcium in 890 g of drinking water.

Step 1: Convert the mass of drinking water to kilograms.

We will use the relation 1 kg = 1000 g.

$890g \times \frac{1kg}{1000g} =0.890kg$

Step 2: Calculate the maximum amount of calcium in 0.890 kg of drinking water

$0.890gH_2O \times \frac{155mgCa}{1kgH_2O} = 138mgCa$

7 0

3 years ago

Derivative for tan(x)

Maksim231197 [3]

Answer:

sec² (x)

Explanation:

Use the trigonometric ratio definition of the tangent function and the quotient rule.

tan(x) = sin(x) / cos(x)

Quotient rule: the derivative of a quotient is:

[the denominator × the derivative of the numerator less the numerator × the derivative of the denominator] / [denominator]²

(f/g)' = [ g×f' - f×g'] / g²

So,

tan(x)' = [ sin(x) / cos(x)]'

[ sin(x) / cos(x)]' = [ cos(x) sin(x)' - sin(x) cos(x)' ] / [cos(x)]²

= [ cos(x)cos(x) + sin(x) sin(x) ] / [ cos(x)]²

= [ cos²(x) + sin²(x) ] / cos²(x)

= 1 / cos² (x)

= sec² (x)

The result is that the derivative of tan(x) is sec² (x)

4 0

3 years ago

Give the IUPAC name for the following structure: 3-chloro-6-methylcyclohexanol 2-methyl-5-chlorocyclohexanol 1-chloro-4-methylcy

Shtirlitz [24]

Answer:

5-chloro-2-methylcyclohexanol

Explanation:

There is no structure for the compound, but we can analyze the proposed options using the IUPAC rules to name organic compounds.

IUPAC rules state that to name an organic compound, first we have to identify the priorities for the functional groups present in the compound. In this case, the priority functional group is the alcohol group, so we will start the counting of the carbons in this group. Then, the counting of carbon atoms is followed by the next substituents so they have the lowest possible numbers, in this case, we can assign the number 2 to the methyl group and 5 to the chloride group, and name the compound in alphabetical order, using commas to separate the words from the numbers and with no space between the words.

Since the other options involve: high countings for the susbtituents groups (3-chloro-6-methylcyclohexanol), wrong assignation of priority functional group (1-chloro-4-methylcyclohexanol), wrong sequence of counting in the compound (2-methyl-3-chlorocyclohexanol) and no alphabetical order to name the compound (2-methyl-5-chlorocyclohexanol), the correct option is:

5-chloro-2-methylcyclohexanol

Have a nice day!

4 0

4 years ago

Is copper II chloride mixed with water an element, compound, or mixture? If it's a mixture is it homogeneous or heterogeneous?

Fittoniya [83]

Answer:

1. mixture

2. Homogenous

Explanation:

Copper II chloride is a compound because it consists of elements that are chemically combined together. When a solute in this case, copper II chloride is mixed with water- a solvent, the result is a homogenous mixture.

Homogenous substances are formed when a solute and a solvent combine, resulting in a mixture with uniform properties. Mixtures can be separated using relevant separation techniques.

7 0

3 years ago