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1 year ago

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Jason’s gas tank can hold 12 gallons of gas. His gas tank was empty and he filled it up 2/3 full. He spent $20.16. How much did

gas cost per gallon?

1 answer:

natita [175]1 year ago

7 0

Answer:

$2.52 per gallon.

Explanation:

$\frac{2}{3} \times 12 = 8$

$8c = 20.16$

$c = 2.52$

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The diagram below shows the measurements of two identical rectangular prisms joined together. Austin says the combined volume of

Ksivusya [100]

Answer:

450 cubic meters

Step-by-step explanation:

( 15 X 5 X 3) + ( 15 x 5 x 3)
225 + 225
450 cubic meters

Austin didn't add the 2 prisms, he multiplied the 1st prism and kept it as the answer.

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3 years ago

Which expression is equivalent to 4^-5 • 3^-5 ?

valkas [14]

The expression equivalent to 4^-5 • 3^-5 is 12^-5

<h3>What are equivalent expressions?</h3>

Equivalent expressions are simply known as expressions with the same solution but different arrangement.

Given the index expressions;

4^-5 • 3^-5

Using the exponent rule, the two values are have different bases but the same exponent and thus, we multiply the bases and leave the exponents the same way.

This can be written as;

4(3) ^ -5

expand the bracket

12^-5

Thus, the expression equivalent to 4^-5 • 3^-5 is 12^-5

Learn more about equivalent expressions here:

brainly.com/question/24734894

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1 year ago

Suppose a population of 140 crickets doubles in size every month. The function f(x) = 140∗2x gives the population after x months

Tema [17]

The equation would then be f(x) = 140 x 2(24)

There will be 6,720 crickets in 2 years

8 0

2 years ago

A 500-gallon tank initially contains 220 gallons of pure distilled water. Brine containing 5 pounds of salt per gallon flows int

Wittaler [7]

Answer: The amount of salt in the tank after 8 minutes is 36.52 pounds.

Step-by-step explanation:

Salt in the tank is modelled by the Principle of Mass Conservation, which states:

(Salt mass rate per unit time to the tank) - (Salt mass per unit time from the tank) = (Salt accumulation rate of the tank)

Flow is measured as the product of salt concentration and flow. A well stirred mixture means that salt concentrations within tank and in the output mass flow are the same. Inflow salt concentration remains constant. Hence:

$c_{0} \cdot f_{in} - c(t) \cdot f_{out} = \frac{d(V_{tank}(t) \cdot c(t))}{dt}$

By expanding the previous equation:

$c_{0} \cdot f_{in} - c(t) \cdot f_{out} = V_{tank}(t) \cdot \frac{dc(t)}{dt} + \frac{dV_{tank}(t)}{dt} \cdot c(t)$

The tank capacity and capacity rate of change given in gallons and gallons per minute are, respectivelly:

$V_{tank} = 220\\\frac{dV_{tank}(t)}{dt} = 0$

Since there is no accumulation within the tank, expression is simplified to this:

$c_{0} \cdot f_{in} - c(t) \cdot f_{out} = V_{tank}(t) \cdot \frac{dc(t)}{dt}$

By rearranging the expression, it is noticed the presence of a First-Order Non-Homogeneous Linear Ordinary Differential Equation:

$V_{tank} \cdot \frac{dc(t)}{dt} + f_{out} \cdot c(t) = c_0 \cdot f_{in}$ , where $c(0) = 0 \frac{pounds}{gallon}$ .

$\frac{dc(t)}{dt} + \frac{f_{out}}{V_{tank}} \cdot c(t) = \frac{c_0}{V_{tank}} \cdot f_{in}$

The solution of this equation is:

$c(t) = \frac{c_{0}}{f_{out}} \cdot ({1-e^{-\frac{f_{out}}{V_{tank}}\cdot t }})$

The salt concentration after 8 minutes is:

$c(8) = 0.166 \frac{pounds}{gallon}$

The instantaneous amount of salt in the tank is:

$m_{salt} = (0.166 \frac{pounds}{gallon}) \cdot (220 gallons)\\m_{salt} = 36.52 pounds$

3 0

3 years ago

Please helppppp !!!!!!!!! Will mark Brianliest !!!!!!!!!!!!!!!!!!

LuckyWell [14K]

Answer:

BH = 16

Step-by-step explanation:

The centroid theorem states that the centroid of a triangle is 2/3 of the distance from a vertex to the midpoint of the opposite side.

That means that BH is 2/3 of the length BF.

BH = (2/3)(BF)

BH = (2/3)(24)

BH = 16

7 0

3 years ago