Let us calculate the median; the 6th observation is 20, so it is 20. We need the 6th observation so that out of the 11 observations we have 5 above the median and 5 below (or equal). We also have that then Q1 is the median of the lowest 5 observations, hence 19 (14,16,19,19,20, the 3rd observation is 19). Similarly, we get that the median for the upper half of the observations, Q3 namely, is 22 (21,21,22,22,23, the 3rd observation is 22). Thus, the interquartile range is 3=Q3-Q1. According to our calculations, all observations are wrong.
Answer: 40
Step-by-step explanation:
We have been given that in ΔJKL, the measure of ∠L=90°, KL = 22 feet, and JK = 54 feet. We are asked to find the measure of angle J to nearest degree.
First of all, we will draw a triangle as shown in the attachment.
We can see from our attachment that side KL is opposite side to angle J and side JK is hypotenuse of right triangle.
We know that sine relates opposite side of right triangle to hypotenuse.
Using inverse sine or arcsin, we will get:
Upon rounding to nearest degree, we will get:
Therefore, the measure of angle J is approximately 24 degrees.
I = p * r * n
i is the interest
p is the principal
r is the interest rate per time period
n is the number of time periods.
in your problem:
i = 900
p = 2000
r = what you want to find
n = 3 years
formula becomes 900 = 2000 * r * 3
solve for r to get r = 900 / 2000 / 3 = .15
that's .15 interest rate per year = 15% per year.
at a nominal interest rate of .15 per year, the interest rate per month would be .15/12 = .0125 per month.
the remaining balance at the end of 6 month is equal to 1907.140183
what is your clear question? it lacks some details
