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Fiesta28 [93]
2 years ago
5

While studying projectile motion, we consider ideal scenarios, where the projectile travels along its trajectory only under the

influence of gravity. In real-world situations, however, other forces act on the projectile. A great example of projectile motion would be a cargo plane that is dropping relief packages to flood victims. In predicting and studying this motion, we might consider gravity, but ignore the horizontal and vertical forces associated with drag (or air friction). Discuss how physics is used in the scenario. (paragraph)
Physics
1 answer:
laiz [17]2 years ago
8 0

The aero plane would only move forward when the thrust force exceeds the drag force.

<h3>What is a projectile?</h3>

The term projectile has to do with a motion that follows a curved trajectory through air. The motion of an airplane that is dropping relief packages to flood victims is a good example of a projectile.

Excluding the horizontal and vertical forces, there are four important forces that act on the airplane;

  • Drag force
  • Gravity
  • Lift
  • Drag
  • Thrust

The aero plane would only move forward when the thrust force exceeds the drag force.

Learn more about balance of forces:brainly.com/question/19127263

#SPJ1

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Directions: Consider a 2-kg bowling ball sits on top of a building that is 40 meters tall. It falls to the ground. Think about t
Ronch [10]

1. The bowling ball have more potential energy as it sit on top of the building

2.The bowling ball have same potential energy and kinetic energy as it is half way through its fall

3. The bowling ball have more kinetic energy just before it hits the ground

4. The potential energy of the bowling ball as it sits on top of the building is 784J

5. The potential energy of the ball as it is half way through the fall, 20 meters high is 392J

6. The kinetic energy of the ball as it is half way through the fall is 392J

7. The kinetic energy of the ball just before it hits the ground is 784J

Explanation:

Calculating potential energy and kinetic energy for all the instances,

1. ball on top of a 40 meters tall building

Potential energy at the top of building with a height of 40m = mgh

P.E = mgh =2*9.8*40= 784J

At the top pf the building since v=0 kinetic energy is zero

2. half way through a fall off a building that is 40 meters tall and travelling 19.8 meters per second

Potential energy when it is half way through fall = mgH

where H represents new height that is equal to 20m

hence P.E=mgH=2*9.8*20= 392J

Kinetic energy  of the ball is \frac{1}{2} mv^{2}  = \frac{1}{2} *2*19.8^{2}=392.04J

3.  Just about to hit the ground from a fall off a building that is 40 meters tall and travelling 28 meters per second.

The potential energy of ball just before it hits the ground = mgh= 2*9.8*0=0J

kinetic energy =\frac{1}{2} mv^{2}= 784J

3 0
3 years ago
Why do all of the parameters, except the independent variable, have to be controlled?
Maru [420]
The independent variable is changed by the experimentor, so it does not have to be changed.
4 0
3 years ago
Read 2 more answers
We sing better in the shower due to standing waves. Assume that your shower is 2.45 m (about 8 ft) tall and can be modeled as an
Ivahew [28]

Answer:

λ = 4.9 m

Explanation:

given,

length of the organ pipe,L = 2.45 m

wavelength of the standing wave = ?

fundamental harmonic is given as,

L= \dfrac{\lambda}{2}

\lambda= 2 \times L

\lambda= 2 \times 2.45

   λ = 4.9 m

Hence, the wavelength of the fundamental harmonic for standing waves in this shower is given by λ = 4.9 m

4 0
4 years ago
Read 2 more answers
if a force of 50N is used to pull a box along the ground, at a distance of 8m. The box moves in the same direction as the force.
ruslelena [56]

Answer:

<h2>400 J</h2>

Explanation:

The work done by an object can be found by using the formula

workdone = force × distance

From the question we have

workdone = 50 × 8

We have the final answer as

<h3>400 J</h3>

Hope this helps you

5 0
3 years ago
PART A:
olga55 [171]

Answer:

4 m/s^{2}

Explanation:

From Equilibrium of forces, The Tension in string is cancelled by the Weight (product of mass and acceleration due to gravity) of the body acting downwards.

The Net force = Mass * Acceleration.

Since Net Force = 20 Newton, Mass = 5kg, therefore;

20 = 5kg * acceleration. Dividing the RHS and LHS of the equation by 5, we have;

Acceleration = \frac{20}{5} which gives 4.

Note: RHS means Right Hand Side.

         LHS means Left Hand Side.

 

7 0
3 years ago
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