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Sphinxa [80]
3 years ago
7

Why do all of the parameters, except the independent variable, have to be controlled?

Physics
2 answers:
Maru [420]3 years ago
4 0
The independent variable is changed by the experimentor, so it does not have to be changed.
Ann [662]3 years ago
4 0

Answer:

To match the cause to its effect

Explanation:

The experimenter alters the independent variable with the hopes of collecting data about how the dependent variable changes in response.Other variables have to be controlled so that any changes of the dependent variable are attributed to the known independent variable. If they are not controlled the experimenter has no way of knowing which variable caused the change. The scientific method would be crippled by that.

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in general, what happens to the energy, order, and spacing of particles when a solid turns to a liquid?
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Calculate the magnitude of the electric field at one corner of a square 2.42 m on a side if the other three corners are occupied
Karolina [17]

Ans:

12500 N/C

Explanation:

Side of square,  a = 2.42 m

q = 4.25 x 10^-6 C

The formula for the electric field is given by

E = \frac{Kq}{r^2}

where, K be the constant = 9 x 10^9 Nm^2/c^2 and r be the distance between the two charges

According to the diagram

BD = \sqrt{2}\times a

where, a be the side of the square

So, Electric field at B due to charge at A

E_{A}=\frac{Kq}{a^2}

E_{A}=\frac{9\times10^{9}\times 4.25 \times 10^{-6}}{2.42^2}

EA = 6531.32 N/C

Electric field at B due to charge at C

E_{C}=\frac{Kq}{a^2}

E_{C}=\frac{9\times10^{9}\times 4.25 \times 10^{-6}}{2.42^2}

Ec = 6531.32 N/C

Electric field at B due to charge at D

E_{D}=\frac{Kq}{2a^2}

E_{D}=\frac{9\times10^{9}\times 4.25 \times 10^{-6}}{2\times 2.42^2}

ED = 3265.66 N/C

Now resolve the components along X axis and Y axis

Ex = EA + ED Cos 45 = 6531.32 + 3265.66 x 0.707 = 8840.5 N/C

Ey = Ec + ED Sin 45 = 6531.32 + 3265.66 x 0.707 = 8840.5 N/C

The resultant electric field at B is given by

E=\sqrt{E_{x}^{2}+E_{y}^{2}}

E=\sqrt{8840.5^{2}+8840.5^{2}}

E = 12500 N/C

Explanation:

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4 years ago
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A potential difference of 18 V is applied to a resistor whose resistance is 240 Ω . What is the current that flows through the r
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Answer:

0.075A

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