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Ilia_Sergeevich [38]
3 years ago
5

2x - 4 = 2(x - 2) solve the following problem and identify the type of equation

Mathematics
1 answer:
Sergio [31]3 years ago
8 0

Answer:

6

Step-by-step explanation:

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What is the answer to 2(x÷6)?​
Jet001 [13]

Answer:

2x÷ 12

Step-by-step explanation:

Use the trick of shaking everybodys hand

2*x=2x

2*6=12

8 0
3 years ago
There are 36 students in Misty in six grade class it's 512s of her students are girls how many girls are in the class
Alexxandr [17]
14.2          because if u divide your numbers you get this                                                                                                                                                                      



6 0
3 years ago
Read 2 more answers
Imma need sum help please
MrRa [10]

Answer:

Step 5

Step-by-step explanation:

The mistake is in step 5.

The previous step was

step \: 4 : 2 + 10 \div 2

The order operations, PEDMAS, must be applied:

We have Addition and Division here,

Using PEDMAS, we must divide first to get:

step \: 5 : 2 + 5

We can now add to get:

step \: 6: 7

Therefore the mistake occurred at step 5

8 0
3 years ago
5c+ 3 < 28 or -4c-2< 14 for c.
sweet-ann [11.9K]

Answer:

c<5, and  c>-4.

<u>Steps used for answers:</u>

5c+3<28 =

1. Subtract 3 from both sides.

5c<28-3

2. Simplify  28-3 to  25.

5c<25

3. Divide both sides by 5.

c<25/5

4. Simplify  25/5 to 5.

c<5

-----------------------

-4c-2<14 =

1. Add 2 to both sides.

-4c<14+2

2. Simplify  14+2 to 16.

-4c<16

3. Divide both sides by -4.

c>-16/4

4. Simplify 16/4 to 4.

c>−4

<u>Done by NeighborhoodDealer</u>

3 0
3 years ago
Read 2 more answers
Find an equation of the line that goes through the points (10,34) and (-1,10)
kotykmax [81]

Answer:

Given points are ( 10 ,34 ) and ( -1 , 10)

Step-by-step explanation:

<em>The </em><em>equation</em><em> </em><em>of </em><em>line </em><em>is </em><em>given </em><em>by </em>

<em>first </em><em>we </em><em>can </em><em>find </em><em>slope </em><em>(</em><em>m</em><em>) </em>

<em>=</em><em> </em><em>(</em><em>y2 </em><em>-</em><em> </em><em>y</em><em>1</em><em>)</em><em> </em><em>/</em><em> </em><em>(</em><em> </em><em>x2</em><em> </em><em>-</em><em> </em><em>x1</em><em>)</em>

<em>=</em><em> </em><em>3</em><em>4</em><em>-</em><em>1</em><em>0</em><em>/</em><em>1</em><em>0</em><em>+</em><em>1</em>

<em> </em><em>=</em><em>2</em><em>4</em><em>/</em><em>1</em><em>1</em>

<em>Now </em><em>the </em><em>equation </em><em>is</em>

<em>y </em><em>-</em><em> </em><em>y1 </em><em>=</em><em> </em><em>m </em><em>(</em><em> </em><em>x </em><em>-</em><em> </em><em>x1) </em>

<em>y </em><em>-</em><em> </em><em>1</em><em>0</em><em> </em><em>=</em><em> </em><em>2</em><em>4</em><em>/</em><em>1</em><em>1</em><em> </em><em>(</em><em> </em><em>x </em><em>+</em><em>1</em><em>1</em><em>)</em>

<em>11 </em><em>(</em><em> </em><em>y </em><em>-</em><em> </em><em>1</em><em>0</em><em> </em><em>)</em><em> </em><em>=</em><em> </em><em>2</em><em>4</em><em> </em><em>(</em><em>x </em><em>+</em><em> </em><em>1</em><em>1</em><em>)</em>

<em>11y </em><em>-</em><em> </em><em>1</em><em>1</em><em>0</em><em> </em><em>=</em><em> </em><em>24x </em><em>+</em><em> </em><em>2</em><em>6</em><em>4</em>

<em>24x </em><em>+</em><em> </em><em>2</em><em>6</em><em>4</em><em> </em><em>+</em><em>110-11y </em><em>=</em><em>0</em>

<em>24x </em><em>-</em><em> </em><em>11y </em><em>+</em><em> </em><em>3</em><em>7</em><em>4</em><em> </em><em>=</em><em> </em><em>0</em>

<em>which </em><em>is </em><em>the </em><em>required </em><em>equation </em>

3 0
3 years ago
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