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Levart [38]
3 years ago
8

Which graph represents a reflection of f(x) = 6(0.5)x across the x-axis?

Mathematics
2 answers:
Musya8 [376]3 years ago
7 0
The required graph is attached.

Marysya12 [62]3 years ago
7 0

Answer: option A on ed2020

Step-by-step explanation:

Good luck on e2020!

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A number decreased by thirty seven or thirty seven less than a number
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frozen [14]

Answer:

54 units squared

Step-by-step explanation:

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3 0
3 years ago
What is a exponential function?
9966 [12]

Answer:

hope I helped also good bless u and your family

Step-by-step explanation:

An exponential function is a mathematical function of the following form: f ( x ) = a x. where x is a variable, and a is a constant called the base of the function. The most commonly encountered exponential-function base is the transcendental number e , which is equal to approximately 2.71828.

6 0
3 years ago
Which pair of funtions is not a pair of inverse functions? please help!!
antiseptic1488 [7]

Answer:

f(x)=\frac{x}{x+20} , g(x)=\frac{20x}{x-1}

Step-by-step explanation:

we know that

To find the inverse of a function, exchange variables x for y and y for x. Then clear the y-variable to get the inverse function.

we will proceed to verify each case to determine the solution of the problem

<u>case A)</u> f(x)=\frac{x+1}{6} , g(x)=6x-1

Find the inverse of f(x)

Let

y=f(x)

Exchange variables x for y and y for x

x=\frac{y+1}{6}

Isolate the variable y

6x=y+1

y=6x-1

Let

f^{-1}(x)=y

f^{-1}(x)=6x-1

therefore

f(x) and g(x) are inverse functions

<u>case B)</u> f(x)=\frac{x-4}{19} , g(x)=19x+4

Find the inverse of f(x)

Let

y=f(x)

Exchange variables x for y and y for x

x=\frac{y-4}{19}

Isolate the variable y

19x=y-4

y=19x+4

Let

f^{-1}(x)=y

f^{-1}(x)=19x+4

therefore

f(x) and g(x) are inverse functions

<u>case C)</u> f(x)=x^{5}, g(x)=\sqrt[5]{x}

Find the inverse of f(x)

Let

y=f(x)

Exchange variables x for y and y for x

x=y^{5}

Isolate the variable y

fifth root both members

y=\sqrt[5]{x}

Let

f^{-1}(x)=y

f^{-1}(x)=\sqrt[5]{x}

therefore

f(x) and g(x) are inverse functions

<u>case D)</u> f(x)=\frac{x}{x+20} , g(x)=\frac{20x}{x-1}

Find the inverse of f(x)

Let

y=f(x)

Exchange variables x for y and y for x

x=\frac{y}{y+20}

Isolate the variable y

x(y+20)=y

xy+20x=y

y-xy=20x

y(1-x)=20x

y=20x/(1-x)

Let

f^{-1}(x)=y

f^{-1}(x)=20x/(1-x)

\frac{20x}{1-x}\neq \frac{20x}{x-1}

therefore

f(x) and g(x) is not a pair of inverse functions

7 0
3 years ago
Read 2 more answers
A line with a slope of 2 passes through the points (0,4) and (-6,v). What is the value of v?
krok68 [10]

To solve this problem, we should create an equation using the given information.  To do this, we should calculate the slope between the two points as if they were regular points, giving us:

change in y/change in x = (v-4)/(-6-0) = (v-4)/(-6)

Since we know that the slope is 2, we can set our calculated value for the slope of the line for the equation (v-4)/(-6) equal to 2, as shown below:

(v-4)/(-6) = 2

To solve this equation, we should multiply both sides of the equation by -6 to get rid of the denominator on the left side of the equation.

v-4 = -12

Next, we should add 4 to both sides of the equation to get the variable v alone on the left side of the equation, as shown below:

v = -8

Therefore, v =-8 is your answer.

Hope this helps!

4 0
3 years ago
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