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solmaris [256]
3 years ago
11

What is the ratio of the area of the trapezoid to the area of the hexagon

Mathematics
1 answer:
Tcecarenko [31]3 years ago
4 0
1:2. Two hexagons fit in a hexagon.
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Raju covers a certain distance in 1 hour and sham covers the same distance in 2 hours , who travels in a higher speed?
dimulka [17.4K]

Answer: Raju travels at a higher speed.

Step-by-step explanation:

Speed =\dfrac{Distance}{Time}

Speed inversely proportional to time.

As time taken to cover a particular distance decreases the speed will increase.

Raju covers a certain distance in 1 hour.

Sham covers the same distance in 2 hours.

1< 2

Thus Raju travels at a higher speed.

5 0
2 years ago
Show another way to write 100 more than 623 ​
____ [38]
There are many ways, but here is one:

x = 100

Since ‘x’ is 100 and we want 100 more, we just need to add ‘x’ to 623

Answer: x + 623 (Make sure you define your ‘x’ value)
4 0
3 years ago
Which values of x and y satisfy 2x − y = 7 and 3x − 2y = 5 simultaneously?
photoshop1234 [79]
To solve problems like this you can either graph or solve mathematically. To do the ladder we need to solve for one variable at a time. So lets cancel one variable out.
Multiply equation 1 by 2
This will give 4x-2y=14
Now we can get rid of y by subtracting 2 from 1
This will give x=9
Plug back in to either equation, i will use equation 2
3(9)-2y=5 simplify
-2y=-22 solve
Y=11
8 0
3 years ago
A rancher wishes to build a fence to enclose a 2250 square yard rectangular field. Along one side the fence is to be made of hea
Bess [88]

Answer:

The least cost of fencing for the rancher is $1200

Step-by-step explanation:

Let <em>x</em> be the width and <em>y </em>the length of the rectangular field.

Let <em>C </em>the total cost of the rectangular field.

The side made of heavy duty material of length of <em>x </em>costs 16 dollars a yard. The three sides not made of heavy duty material cost $4 per yard, their side lengths are <em>x, y, y</em>.  Thus

C=4x+4y+4y+16x\\C=20x+8y

We know that the total area of rectangular field should be 2250 square yards,

x\cdot y=2250

We can say that y=\frac{2250}{x}

Substituting into the total cost of the rectangular field, we get

C=20x+8(\frac{2250}{x})\\\\C=20x+\frac{18000}{x}

We have to figure out where the function is increasing and decreasing. Differentiating,

\frac{d}{dx}C=\frac{d}{dx}\left(20x+\frac{18000}{x}\right)\\\\C'=20-\frac{18000}{x^2}

Next, we find the critical points of the derivative

20-\frac{18000}{x^2}=0\\\\20x^2-\frac{18000}{x^2}x^2=0\cdot \:x^2\\\\20x^2-18000=0\\\\20x^2-18000+18000=0+18000\\\\20x^2=18000\\\\\frac{20x^2}{20}=\frac{18000}{20}\\\\x^2=900\\\\\mathrm{For\:}x^2=f\left(a\right)\mathrm{\:the\:solutions\:are\:}x=\sqrt{f\left(a\right)},\:\:-\sqrt{f\left(a\right)}\\\\x=\sqrt{900},\:x=-\sqrt{900}\\\\x=30,\:x=-30

Because the length is always positive the only point we take is x=30. We thus test the intervals (0, 30) and (30, \infty)

C'(20)=20-\frac{18000}{20^2} = -25 < 0\\\\C'(40)= 20-\frac{18000}{20^2} = 8.75 >0

we see that total cost function is decreasing on (0, 30) and increasing on (30, \infty). Therefore, the minimum is attained at x=30, so the minimal cost is

C(30)=20(30)+\frac{18000}{30}\\C(30)=1200

The least cost of fencing for the rancher is $1200

Here’s the diagram:

3 0
2 years ago
5x + 10y = 18
SOVA2 [1]
5x + 10y = 18

x = y -6, we substitute this into first equation.

5x + 10y = 18

5*(y - 6) + 10y = 18

5y - 30 + 10y = 18

So it the last option from the top.
4 0
3 years ago
Read 2 more answers
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