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shtirl [24]
3 years ago
12

Please solve the underlined question thank you!

Mathematics
2 answers:
alexgriva [62]3 years ago
6 0

Answer:

Step-by-step explanation:

50x^2 - 72 = 0

2(25x^2 - 36) = 0

2(5x + 6)(5x - 6) = 0

5x + 6 =0; x = -6/5

5x - 6 = 0; x = 6/5

Answer

x = ± 6/5

----------------------

9x^2 + 6x = 10

Divide both sides by 9

x^2 + 2/3 x = 10/9

b/2 = 2/3 * 1/2 = 2/6 = 1/3

As you know (1/3)^2 = 1/9

so add both sides by 1/9

x^2 + 2/3 x + 1/9 = 10/9 + 1/9

(x + 1/3)^2 = 11/9

x + 1/3 = ±√11/9

x = ± √11 / 3  - 1/3

Answer:

x = ± √11 / 3  - 1/3

notsponge [240]3 years ago
5 0

Answer:

Step-by-step explanation:

4

Take out a 2 to begin with.

2(25x^2 - 36)    This is the difference of squares (inside the brackets). Factor.

2*(5x - 6)(5x + 6)

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Alex777 [14]
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3 0
3 years ago
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Express the sum of the polymonial 3x^2+15x-56 and the square of the binomial (x-8) as a polynomial in standard form.
tester [92]

Given:

Polynomial is 3x^2+15x-56.

To find:

The sum of given polynomial and the square of the binomial (x-8) as a polynomial in standard form.

Solution:

The sum of given polynomial and the square of the binomial (x-8) is

3x^2+15x-56+(x-8)^2

=3x^2+15x-56+x^2-2(x)(8)+8^2    [\because (a-b)^2=a^2-2ab+b^2]

=3x^2+15x-56+x^2-16x+64

On combining like terms, we get

=(3x^2+x^2)+(15x-16x)+(-56+64)

=4x^2-x+8

Therefore, the sum of given polynomial and the square of the binomial (x-8) as a polynomial in standard form is 4x^2-x+8.

7 0
3 years ago
1. How much greater is -20x^2+5x+17 than -19x^2+20x+18
ehidna [41]

Answer:

1. -x²-15x-1

2. -33x⁷+10x⁶-14x⁵+4x⁴+11x²-5x+32

Step-by-step explanation:

-20x^2+5x+17 - (-19x^2+20x+18)

-20x² + 19x² + 5x - 20x + 17 - 18

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-20x⁷ - 13x⁷ + 10x⁶ - 14x⁵ + 4x⁴ + 11x² - 5x + 15 + 17

-33x⁷ + 10x⁶ - 14x⁵ + 4x⁴ + 11x² - 5x + 32

8 0
3 years ago
Read 2 more answers
0.2343217 Is it rational or irrational
tia_tia [17]
Irrational because it can not be written as a fraction
8 0
2 years ago
The rule for this number sequence is (n+3) x 2
zzz [600]
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Happy to Help!
8 0
3 years ago
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