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mojhsa [17]
1 year ago
8

What is the shortest horizontal shift of a sine curve that will turn it into a cosine curve?

Mathematics
1 answer:
77julia77 [94]1 year ago
3 0

The shortest horizontal shift of a sine curve that will turn it into a cosine curve is a shift of <u>90°( π/2 radians)</u>.

The function y = sin x defines a sine wave as a geometric waveform that oscillates (moves up, down, or side to side) frequently. It is an s-shaped, smooth wave that oscillates above and below zero, to put it another way.

Technical analysis and trading both employ sine waves to assist spot oscillator-related patterns and cross-overs.

Similar to the sine graph, the cosine graph is an up-down graph. The sine graph and cos graph are identical except that the sine graph begins at 0, whereas the cos graph begins at <u>90° (or π/2)</u>. The cosine (cos) graph shown below starts at 1 and drops to -1 before rising once again.

Thus, the shortest horizontal shift of a sine curve that will turn it into a cosine curve is a shift of <u>90°( or π/2 radians)</u>.

Learn more about sine and cosine curves at

brainly.com/question/17075439

#SPJ4

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F(x) = x² + 4x - 12

x = -b/2a
x = -(4)/2(1)
x = -4/2
x = 2

f(x) = x² + 4x - 12
f(2) = (2)² + 4(2) - 12
f(2) = 4 + 8 - 12
f(2) = 12 - 12
f(2) = 0

The vertex of the function is (2,0).
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Jonathan is in a class of 15 boys and 35 girls.40%of the students in the class take the bus to school how many students do not t
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Factor completely, the expression: 2x^3-2x^2-12x
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Write the equation in slope-intercept form then change it to standard form with integer coefficients.
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Answer:

1. Slope-intercept form:   y = 2x - 4

Standard form:   2x - y = 4

2. Slope-intercept form:  y = \dfrac12x - 1

Standard form:             x - 2y = 2

3. Slope-intercept form:   y = \dfrac45x + \dfrac{21}{5}

Standard form:            4x -5y = - 21

Step-by-step explanation:

Slope intercept form:   y = mx + b

where:

  • y = y-coordinate
  • m = slope
  • x = x-coordinate
  • b = y-intercept

Standard form:  Ax + By = C

\textsf{1.  as} \ m=2: \ \ y = 2x + b

   \textsf{at} \  (6, 8): \ \ 8 = 2(6) + b

   \implies b = -4

Slope-intercept form:   y = 2x - 4

Standard form:   2x - y = 4

\textsf{2.  as} \  \ m = \dfrac12: \ \ y = \dfrac12x + b

    \textsf{at} \  (4, 1): \ \ 1 = \dfrac12(4) + b

    \implies b = -1

Slope-intercept form:  y = \dfrac12x - 1

Standard form:             x - 2y = 2

\textsf{3.  as} \  \ m = \dfrac45: \ \ y = \dfrac45x + b

   \textsf{at} \  (1,5): \ \ 5 = \dfrac45(1) + b

   \implies b = \dfrac{21}{5}

Slope-intercept form:   y = \dfrac45x + \dfrac{21}{5}

Standard form:            4x -5y = - 21

7 0
2 years ago
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