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koban [17]
2 years ago
8

What is the standard form for 85 million 16 thousand twelve

Mathematics
1 answer:
erastova [34]2 years ago
5 0
Standard form of given question :8.5016012×10^7
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M is the midpoint of AB. Find the coordinates of B given A(3,8) and M(5,4).
Harlamova29_29 [7]

Answer: B(7,0)

Step-by-step explanation:

Since coordinate of A(3,8) and M(5,4), where M is the midpoint of AB.

Let the coordinate of B be (x,y)

Therefore, the distance AM is equal to distance MB.

Distance = sqrt{ (5 - 3)² + (4-8)² } =sqrt { (x-5)² + (y-4)²}

Comparing corresponding coordinates,

5-3 = x-5

x= 5+5-3 = 7

4-8 = y-4

y= 4-8+4= 0

Therefore, the coordinate of B is (7,0)

3 0
3 years ago
Solve the equation.<br><br> 5d = 17.1<br><br><br> 12.1<br><br> 22.1<br><br> 85.5<br><br> 3.42
Rudiy27

Hello there!


5d = 17.1

The equation is asking you to find the value for "d". How to do that? Well, all you have to do is divide both side by 5.

5d/5 = 17.1

d = 3.42  

That's your answer!


You can even double check your work, if you want to. How? Well, you just need to replace 3.42 where it belongs.

5(3.42) = 17.1

17.1 = 17.1

True!


Let me know if you have additional questions. As always, it is my pleasure to help students like you!

7 0
2 years ago
Read 2 more answers
Using pemdas what’s the correct solution
SSSSS [86.1K]

4- 2/3 (4-1/6) divided by 3/4

parenthesis first

4 - 2/3 (3 5/6) divided by 3/4

change to an improper fraction (6*3+5)/6

4 - 2/3 ( 23/6)divided by 3/4

4 - 46/18 divide by3/4

copy dot flip

4 - 46/18 * 4/3

4 - 23/9 * 4/3

4 - 92/27

get a common denominator of 27

4*27/27 -92/27

108/27 - 92/27

16/27

4 0
3 years ago
Read 2 more answers
A car takes 54.9 seconds to travel 1 mile. How long does it take the car to travel 4.3 miles? First round to the nearest whole n
fiasKO [112]

Answer: Rounded: 236 seconds

Not rounded: 236.07 seconds

Step-by-step explanation: We know that it takes the car 54.9 seconds to travel one mile, and we know that 1 times 4.3 is 4.3, so 4.3 times 54.9 equals 236.07 seconds.

5 0
3 years ago
Whats the intrgral of <img src="https://tex.z-dn.net/?f=%20%5Cint%20%20%5Cfrac%7Bx%5E2%2Bx-3%7D%7B%28x%5E3%2Bx%5E2-4x-4%29%5E2%7
rosijanka [135]
\displaystyle\int\frac{x^2+x-3}{(x^3+x^2-4x-4)^2}\,\mathrm dx

Notice that x^3+x^2-4x-4=x^2(x+1)-4(x+1)=(x-2)(x+2)(x+1). Decompose the integrand into partial fractions:

\dfrac{x^2+x-3}{(x-2)^2(x+2)^2(x+1)^2}
=\dfrac1{3(x+1)}-\dfrac{11}{32(x+2)}-\dfrac1{3(x+1)^2}-\dfrac1{16(x+2)^2}+\dfrac1{96(x-2)}+\dfrac1{48(x-2)^2}

Integrating term-by-term, you get

\displaystyle\int\frac{x^2+x-3}{(x^3+x^2-4x-4)^2}\,\mathrm dx
=-\dfrac1{48(x-2)}+\dfrac1{3(x+1)}+\dfrac1{16(x+2)}+\dfrac1{96}\ln|x-2|+\dfrac13\ln|x+1|-\dfrac{11}{32}\ln|x+2|+C
5 0
3 years ago
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