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VARVARA [1.3K]
1 year ago
10

What is the value of x to the nearest degree?

Mathematics
1 answer:
astraxan [27]1 year ago
5 0
Using tan ( opp / adj )

2nd tan = 13 / 6
x = 65.22

to the nearest degree, it would be 65°.
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Find the length of the missing leg. Round to the nearest tenth if necessary
mestny [16]
I’m going to use Pythagorus theorem for his question. // firstly I would do 20^2 + 16^2 = 656 // we them square root that number, so the square root of 656 is 25.61, meaning the missing length is 25.6
4 0
2 years ago
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Six oranges cost 5.34. How much does 1 Orange cost?
ikadub [295]

Divide the total cost with the amount there is

5.34/6 = 0.89

Each orange costs $0.89, or 89 cents

hope this helps

6 0
3 years ago
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You spend $30.40 on 4 CDs. Each CD costs the same amount and is on sale for 80% of the original price.
gizmo_the_mogwai [7]
Answer: The original price is $9.5
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4 0
2 years ago
Unoccupied seats on flights cause airlines to lose revenue. Suppose a large airline wants to estimate its average number of unoc
Bingel [31]

Answer:

We need a sample size of at least 719

Step-by-step explanation:

We have that to find our \alpha level, that is the subtraction of 1 by the confidence interval divided by 2. So:

\alpha = \frac{1-0.95}{2} = 0.025

Now, we have to find z in the Ztable as such z has a pvalue of 1-\alpha.

So it is z with a pvalue of 1-0.025 = 0.975, so z = 1.96

Now, find the margin of error M as such

M = z*\frac{\sigma}{\sqrt{n}}

In which \sigma is the standard deviation of the population and n is the size of the sample.

How large a sample size is required to vary population mean within 0.30 seat of the sample mean with 95% confidence interval?

This is at least n, in which n is found when M = 0.3, \sigma = 4.103. So

M = z*\frac{\sigma}{\sqrt{n}}

0.3 = 1.96*\frac{4.103}{\sqrt{n}}

0.3\sqrt{n} = 1.96*4.103

\sqrt{n} = \frac{1.96*4.103}{0.3}

(\sqrt{n})^{2} = (\frac{1.96*4.103}{0.3})^{2}

n = 718.57

Rouding up

We need a sample size of at least 719

6 0
2 years ago
A runner’s distribution of times for running 1,000 meters has a mean of 4.5 minutes with a standard deviation of 0.75 minutes. O
7nadin3 [17]
The answer would be 3.75
I just know
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2 years ago
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