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Yuri [45]
2 years ago
12

5 consecutive house numbers in a

Mathematics
1 answer:
ELEN [110]2 years ago
8 0

Answer:

81

Step-by-step explanation:

by dividing the smallest number from the bigger number to get the last house

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What is 851 divided by 48?
makvit [3.9K]

Answer:

= 17.7 ( rounded off to one decimal place)

STAY SAFE, GOD BLESS YOU :)

Step-by-step explanation:

851 ÷ 48

= 17.7291

= 17.7 ( rounded off to one decimal place)

3 0
3 years ago
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Which galaxy is the farthest from Earth?<br>galaxy a<br>galaxy b<br>galaxy c<br>galaxy d​
harina [27]
Galaxy c is the farthest
5 0
3 years ago
Need help now!! 20 points!!
Gelneren [198K]

When you have something like this, all you need to do is substitute the values, the last is for what value of x

For the first one;

((x^2+1)+(x-2))(2)

(x^2+x-1)(2)

(2)^2+(2)-1

4+2-1

5

For the second one;

((x^2+1)-(x-2))(3)

(x^2-x+3)(3)

(3)^2-(3)+3

9-3+3

9

For the last one;

3(x^2+1)(7)+2(x-2)(3)

3((7)^2+7)+2((3)-2)

3(49+7)+2(3-2)

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168+2

170

3 0
3 years ago
WILL GIVE BEST RESPONSE
tino4ka555 [31]
We will use demonstration of recurrences<span>1) for n=1, 10= 5*1(1+1)=5*2=10, it is just
2) assume that the equation </span>10 + 30 + 60 + ... + 10n = 5n(n + 1) is true, <span>for all positive integers n>=1
</span>3) let's show that the equation<span> is also true for n+1, n>=1
</span><span>10 + 30 + 60 + ... + 10(n+1) = 5(n+1)(n + 2)
</span>let be N=n+1, N is integer because of n+1, so we have
<span>10 + 30 + 60 + ... + 10N = 5N(N+1), it is true according 2)
</span>so the equation<span> is also true for n+1, 
</span>finally, 10 + 30 + 60 + ... + 10n = 5n(n + 1) is always true for all positive integers n.
<span>
</span>
4 0
3 years ago
0.1 is a rational number because it can be written as
Gnesinka [82]

Answer:

because it can be written in the <u>form</u><u> </u>of p/q

Where p and q are integers, and q is <u>not</u> equal to zero.

8 0
2 years ago
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