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Svetradugi [14.3K]
3 years ago
7

Type the correct answer in each box Functions h and k are inverse functions, and both are defined for all real number Using this

relationship, what is the value of each function composition? (h*k)(3) ​
Mathematics
2 answers:
Leya [2.2K]3 years ago
7 0

Answer:

In photo below

Explanation:

In photo below

Novosadov [1.4K]3 years ago
4 0
Type the correct answer in each box
functions HNK or inverse functions in both are defined for all real numbers using this relationship what is the value of each function composition
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3x+5y-4=0<br> what is the slope and y-intercept?
zaharov [31]

Answer:

3x + 5y - 4 = 0 \\ 3x + 5y = 4 \\ 5y = 4 - 3x \\ y =  \frac{4}{5}  -  \frac{3}{5} x \\ y = mx + c \\ slope = m =  \frac{ - 3}{5}  \\ y \: intersept = c =  \frac{4}{5}  \\ thank \: you

5 0
3 years ago
Tay is making jam. The recipe calls for `3` strawberries for each apple.
puteri [66]

Answer:

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4 0
3 years ago
A student was required to multiply a number by 4 and add 6 to it. Instead he added 6 to it first and then multiplied by 4. What
GalinKa [24]

Answer:

The correct answer is 18

the correct expression is (4n+6)

Step-by-step explanation:

let the number be n

therefore  if he is required to multiply n by 4 and added to 6 we have

(4n+6)= 0-----1

given that he did otherwise by adding 6 to n and multiply by 4 we have

(n+6)4= 36------2

Firstly we need to solve for n in equation 2

4n+24= 36\\4n= 36-24\\4n= 12\\

Dividing both sides by 4 we have

n= \frac{12}{4\\}\\n= 3

In order to solve for the correct answer let us input n=3 in equation 1 we have

=(4n+6)= 0-------1\\=(4*3+6)= 0\\=(12+6)=0\\= 18

7 0
3 years ago
I need help please.
VARVARA [1.3K]

Answer:

that anzwer will be (9) ok

3 0
3 years ago
Read 2 more answers
Expressed as a product of its prime factors in index form, a number N is
Elena-2011 [213]

<u>ANSWER</u>



5N^2=3^{2} \times 5^{5} \times x^{6}



<u>EXPLANATION</u>


N=3\times5^2 \times x^3.


5N^2=5(3\times5^2 \times x^3)^2


Recall this property of exponents;


(a^m)^2=a^{m} \times a^m



So our product becomes;


5N^2=5(3\times5^2 \times x^3) \times (3\times5^2 \times x^3)



5N^2=5\times 3\times 3 \times 5^2 \times 5^2 \times x^3 \times x^3


5N^2=3\times 3\times 5 \times 5^2 \times 5^2 \times x^3 \times x^3



Recall this law of exponents:


a^m \times a^n =a ^{m+n}


5N^2=3^{1+1} \times 5^{1+2+2} \times x^{3+3}


5N^2=3^{2} \times 5^{5} \times x^{6}




7 0
3 years ago
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