3B + 4T = 11.33
9B + 5T = 23.56
Solve by elimination:
Multiply the first equation by -3 to get -9B where the 3B is
so that it will cancel with the 9B when the equations are added.
-9B - 12T = -33.99
9B + 5T = 23.56
------------------
-7T = -10.43
T = $1.49
Substitute in
3B + 4T = 11.33
3B + 4(1.49) = 11.33
3B + 5.96 = 11.33
3B = 5.37
B = $1.79
A taco costs $1.49 and a burrito costs $1.79.
Therefore 5 burritos and 7 tacos will cost
5B + 7T = 5($1.79) + 7($1.49) = $19.38
So the problem ask to calculate and covert the said equation or expression to the form of ca^pb^q where as all of the variables is a number. So base in that information and following some formula, the answer would be a^(-3/2)b. I hope you are satisfied with my answer
You know a1.
So find a2, a3, and so on until a7.
a(1) = 12
a(2) = 16
a(3) = 20
a(4) = 24
a(5) = 28
a(6) = 32
a(7) = 36
Each is 4 more than the previous.
